When \(10.0 \mathrm{g}\) zinc and \(8.0 \mathrm{g}\) sulfur are allowed to react, all the zinc is consumed, \(14.9 \mathrm{g}\) zinc sulfide is produced, and the mass of unreacted sulfur remaining is (a) \(2.0 \mathrm{g}\) (b) \(3.1 g\) (c) \(4.9 \mathrm{g}\) (d) impossible to predict from this information alone

Short Answer

Expert verified
The mass of the unreacted sulfur remaining is \(3.1 \mathrm{g}\).

Step by step solution

01

Identify the mass of the initial reactants

The mass of the initial reactants are given in the problem statement: 10.0g zinc and 8.0g sulfur. So total mass of the initial reactants is \(10.0 \mathrm{g} + 8.0 \mathrm{g} = 18.0 \mathrm{g}\).
02

Calculate the mass of the zinc sulfide produced

All the zinc is consumed and 14.9g of zinc sulfide is produced. This gives us the total mass of the reaction products.
03

Find the mass of the unreacted sulfur

The mass of unreacted sulfur can be found by subtracting the mass of the zinc sulfide produced from the total mass of the initial reactants. That is \(18.0 \mathrm{g} - 14.9 \mathrm{g} = 3.1 \mathrm{g}\). Thus the remaining mass of sulfur is 3.1g.

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