Of the following statements concerning electrochemical cells, the correct ones are: (a) The cathode is the negative electrode in both voltaic and electrolytic cells. (b) The function of a salt bridge is to permit the migration of electrons between the half-cell compartments of an electrochemical cell. (c) The anode is the negative electrode in a voltaic cell. (d) Electrons leave the cell from either the cathode or the anode, depending on what electrodes are used. (e) Reduction occurs at the cathode in both voltaic and electrolytic cells. (f) If electric current is drawn from a voltaic cell long enough, the cell becomes an electrolytic cell. (g) The cell reaction is an oxidationreduction reaction.

Short Answer

Expert verified
The correct statements are: (c) The anode is the negative electrode in a voltaic cell, (e) Reduction occurs at the cathode in both voltaic and electrolytic cells, and (g) The cell reaction is an oxidation-reduction reaction.

Step by step solution

01

Evaluate statement (a)

The cathode is the positive electrode in a voltaic cell but becomes the negative one in an electrolytic cell when an external voltage is applied. So, statement (a) is incorrect.
02

Evaluate statement (b)

A salt bridge does not permit the migration of electrons but of ions, maintaining neutrality in the half-cells. Thus, the statement (b) is incorrect.
03

Evaluate statement (c)

The anode is the negative electrode in a voltaic cell, so statement (c) is correct.
04

Evaluate statement (d)

Regardless of the electrodes used, electrons always enter the cell at the cathode and leave the cell at the anode. So, statement (d) is wrong.
05

Evaluate statement (e)

Reduction always occurs at the cathode, whether it is a voltaic or electrolytic cell. Hence, statement (e) is correct.
06

Evaluate statement (f)

Drawing electrical current from a voltaic cell for a long time does not make it an electrolytic cell. Therefore, statement (f) is incorrect.
07

Evaluate statement (g)

The cell reaction in both voltaic and electrolytic cells is always a redox (oxidation-reduction) reaction. Thus, statement (g) is correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Voltaic and Electrolytic Cells
Understanding the differences between voltaic (galvanic) and electrolytic cells is crucial for mastering electrochemistry. Voltaic cells convert chemical energy into electrical energy using spontaneous redox reactions. They are the basis for batteries, where the chemical reaction creates a flow of electrons from the anode to the cathode through an external circuit.

Electrolytic cells, on the other hand, require an external source of electricity to induce non-spontaneous chemical reactions. This process is commonly used in electroplating, where a metal is deposited onto an electrode. The key distinction lies in their operating principles: voltaic cells harness spontaneous reactions, while electrolytic cells drive non-spontaneous reactions with external power.

They share similar setups with two electrodes, an electrolyte solution, and sometimes a salt bridge to maintain charge balance by allowing ions, not electrons, to move between compartments. It's important to remember that electrons never physically pass through the salt bridge.
Cathode and Anode in Electrochemistry
In electrochemical cells, electrodes play vital roles and are known as the cathode and anode. The anode is where oxidation occurs; it loses electrons. Conversely, at the cathode, reduction takes place as it gains electrons.

Determining whether an electrode is positive or negative depends on the cell type. In a voltaic cell, the anode is negative since the cell works based on spontaneous reactions, pushing electrons out of the anode through the circuit. The cathode is positive, accepting these electrons to complete the circuit. However, this polarity is reversed in an electrolytic cell because external energy is provided to drive the reactions. Here the cathode is negative, receiving electrons from the external source, while the anode is positive. Keeping these distinctions clear is essential for understanding the flow of electrons and the functioning of electrochemical cells.
Redox (Oxidation-Reduction) Reactions
Redox reactions are at the heart of electrochemical cells. These reactions involve the transfer of electrons between chemical species. When a substance loses electrons, we term it oxidation; when it gains electrons, it's called reduction.

These reactions are coupled—whenever one species is oxidized, another is simultaneously reduced. This electron transfer process is what drives the current in voltaic cells and is forced by an external power source in electrolytic cells. An easy way to remember the distinction is the mnemonic 'OIL RIG': Oxidation Is Loss, Reduction Is Gain.

In voltaic cells, the spontaneous redox reaction generates electric current, while in electrolytic cells, the applied current induces a redox reaction. Both types of cells are fundamental in various technologies, from powering portable electronics to synthesizing valuable chemicals.

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Most popular questions from this chapter

A quantity of electric charge brings about the deposition of \(3.28 \mathrm{g}\) Cu at a cathode during the electrolysis of a solution containing \(\mathrm{Cu}^{2+}(\text { aq })\). What volume of \(\mathrm{H}_{2}(\mathrm{g}),\) measured at \(28.2^{\circ} \mathrm{C}\) and \(763 \mathrm{mm} \mathrm{Hg},\) would be produced by this same quantity of electric charge in the reduction of \(\mathrm{H}^{+}(\) aq) at a cathode?

Show that for nonstandard conditions the temperature variation of a cell potential is $$E\left(T_{1}\right)-E\left(T_{2}\right)=\left(T_{1}-T_{2}\right) \frac{\left(\Delta S^{\circ}-R \ln Q\right)}{z F}$$ where \(E\left(T_{1}\right)\) and \(E\left(T_{2}\right)\) are the cell potentials at \(T_{1}\) and \(T_{2},\) respectively. We have assumed that the value of \(Q\) is maintained at a constant value. For the nonstandard cell below, the potential drops from \(0.394 \mathrm{V}\) at \(50.0^{\circ} \mathrm{C}\) to \(0.370 \mathrm{V}\) at \(25.0^{\circ} \mathrm{C} .\) Calculate \(Q\) \(\Delta H^{\circ},\) and \(\Delta S^{\circ}\) for the reaction, and calculate \(K\) for the two temperatures. $$\mathrm{Cu}(\mathrm{s})\left|\mathrm{Cu}^{2+}(\mathrm{aq}) \| \mathrm{Fe}^{3+}(\mathrm{aq}), \mathrm{Fe}^{2+}(\mathrm{aq})\right| \mathrm{Pt}(\mathrm{s})$$ Choose concentrations of the species involved in the cell reaction that give the value of \(Q\) that you have calculated, and then determine the equilibrium concentrations of the species at \(50.0^{\circ} \mathrm{C}\)

\(E_{\text {cathode }}^{\circ}=(2.71-2.310) V=+0.40 \mathrm{V}\)

In the construction of the Statue of Liberty, a framework of iron ribs was covered with thin sheets of copper less than \(2.5 \mathrm{mm}\) thick. A layer of asbestos separated the copper skin and iron framework. Over time, the asbestos wore away and the iron ribs corroded. Some of the ribs lost more than half their mass in the 100 years before the statue was restored. At the same time, the copper skin lost only about \(4 \%\) of its thickness. Use electrochemical principles to explain these observations.

A test for completeness of electrodeposition of \(\mathrm{Cu}\) from a solution of \(\mathrm{Cu}^{2+}(\mathrm{aq})\) is to add \(\mathrm{NH}_{3}(\mathrm{aq}) .\) A blue color signifies the formation of the complex ion \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}\left(K_{\mathrm{f}}=1.1 \times 10^{13}\right) .\) Let \(250.0 \mathrm{mL}\) of \(0.1000 \mathrm{M} \mathrm{CuSO}_{4}(\text { aq })\) be electrolyzed with a \(3.512 \mathrm{A}\) current for 1368 s. At this time, add a sufficient quantity of \(\mathrm{NH}_{3}(\text { aq })\) to complex any remaining \(\mathrm{Cu}^{2+}\) and to maintain a free \(\left[\mathrm{NH}_{3}\right]=0.10 \mathrm{M} .\) If \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}\) is detectable at concentrations as low as \(1 \times 10^{-5} \mathrm{M}\) should the blue color appear?

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