$$E_{\text {cathode }}^{\circ}=(2.71-2.310) V=+0.40 V$$VVV

Short Answer

Expert verified
The standard potential of the cathode is \(0.40 V\).

Step by step solution

01

Understand the Given

This exercise works on the standard potential of a cathode in an electrochemical cell. The standard potential \(E_{cathode}^{\circ}\) is given by the formula \(E_{cathode}^{\circ}=E_{anode}^{0}-E_{cathode}^{0}\), where the standard potential of the anode and cathode are provided.
02

Substitute the Known Values

Substitute the given standard potentials into the standard cathode potential formula: \(E_{cathode}^{\circ} = 2.71 V - 2.310 V\).
03

Perform the Calculation

Perform the subtraction to calculate the standard potential of the cathode: \(E_{cathode}^{\circ} = 2.71 V - 2.310 V = 0.40 V\). The voltage is positive, indicating that the reaction can occur spontaneously under standard conditions.

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Most popular questions from this chapter

A concentration cell is constructed of two hydrogen electrodes: one immersed in a solution with \(\left[\mathrm{H}^{+}\right]=1.0 \mathrm{M}\) and the other in \(0.65 \mathrm{M} \mathrm{KOH}\) (a) Determine \(E_{\text {cell for the reaction that occurs. }}\) (b) Compare this value of \(E_{\text {cell }}\) with \(E^{\circ}\) for the reduction of \(\mathrm{H}_{2} \mathrm{O}\) to \(\mathrm{H}_{2}(\mathrm{g})\) in basic solution, and explain the relationship between them.

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