Silver tarnish is mainly \(\mathrm{Ag}_{2} \mathrm{S}\) : $$\begin{array}{r}\mathrm{Ag}_{2} \mathrm{S}(\mathrm{s})+2 \mathrm{e}^{-} \longrightarrow 2 \mathrm{Ag}(\mathrm{s})+\mathrm{S}^{2-}(\mathrm{aq}) \\\E^{\circ}=-0.691 \mathrm{V}\end{array}$$ A tarnished silver spoon is placed in contact with a commercially available metallic product in a glass baking dish. Boiling water, to which some \(\mathrm{NaHCO}_{3}\) has been added, is poured into the dish, and the product and spoon are completely covered. Within a short time, the removal of tarnish from the spoon begins. (a) What metal or metals are in the product? (b) What is the probable reaction that occurs? (c) What do you suppose is the function of the \(\mathrm{NaHCO}_{3} ?\) (d) An advertisement for the product appears to make two claims: (1) No chemicals are involved, and (2) the product will never need to be replaced. How valid are these claims? Explain.

Short Answer

Expert verified
(a) The most probable metal in the product is Aluminum. (b) The probable reaction is \( 3 Ag2S + 2 Al \rightarrow 6 Ag + Al2S3 \). (c) The function of \( \mathrm{NaHCO}_{3} \) or baking soda is likely to provide a medium conducive to the transfer of electrons, facilitating the reduction reaction. (d) The claim that 'no chemicals are involved' is somewhat misleading while the claim that 'the product will never need to be replaced' is possibly valid until the aluminum is thoroughly reacted with.

Step by step solution

01

Identifying the Metal

The tarnish is being removed from the silver spoon. This indicates that a redox reaction is in place and the tarnish is being reduced back to silver. One such metal that could cause this reduction is aluminum, as it is highly reactive and easily donates electrons to silver ions in the tarnish.
02

Formulating the Reaction

The reaction could be: \( 3 Ag2S + 2 Al \rightarrow 6 Ag + Al2S3 \). The reaction suggests that aluminum reacts with silver sulfide, reducing it back to silver.
03

Function of \( \mathrm{NaHCO}_{3} \)

The function of the \( \mathrm{NaHCO}_{3} \) or baking soda, may be to provide a medium conducive to the transfer of electrons, facilitating the reduction reaction.
04

Examining Claims

The claims require the understanding of chemicals and their involvement. In terms of the claim that 'no chemicals are involved', it is somewhat misleading as even water and \( \mathrm{NaHCO}_{3} \) are chemicals. The second claim, that 'the product will never need to be replaced', is possible if the product in question is the aluminum foil or plate used, as the aluminum can possibly be reused up to the point it's entirely reacted with.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Redox Reaction
In the context of silver tarnish removal, a redox reaction—short for reduction-oxidation reaction—is the chemical process at play. Redox reactions are a type of chemical reaction where electrons are transferred between two substances. During this transfer, one substance is oxidized (loss of electrons) and another is reduced (gain of electrons).For a tarnished silver spoon, the tarnish is a layer of silver sulfide \( \mathrm{Ag}_2 \mathrm{S} \). The redox reaction involves the reduction of silver sulfide back to silver metal. A metal, likely aluminum in this case, gets oxidized, thereby donating electrons that transform the silver sulfide (reductant) into elemental silver (reducing agent).Understanding these reactions helps explain why certain home remedies, like lining a container with aluminum foil and adding boiling water and baking soda, can remove tarnish. The aluminum foil undergoes oxidation, and in exchange, the silver sulfide reduces to silver, restoring the shine to the silver object. Considering this, the claim of 'no chemicals involved' in such a process is incorrect as the aluminum, water, and baking soda are all chemicals participating in the redox reaction.
Chemical Reactions in Everyday Life
Chemical reactions are not just confined to laboratory settings; they are a part of our day-to-day lives. For example, when a silver spoon becomes tarnished over time, it's due to a chemical reaction between silver and sulfur-containing substances in the air, leading to the formation of silver sulfide.In a redox reaction for tarnish removal, everyday materials can facilitate the reaction. Baking soda \(\mathrm{NaHCO}_{3}\), a common household chemical, is often used as an electrolyte to create a conductive solution, which can assist in the transfer of electrons necessary for the redox reaction between the aluminum and the silver sulfide tarnish.Even the digestion of food in our bodies involves chemical reactions. When products are marketed as not using chemicals, it's a misconception—even the air we breathe and the water we drink are composed of chemicals. Thus, educating oneself on the basics of chemistry can help navigate through marketing claims and understand the science behind common household processes.
Electrochemical Series
The electrochemical series, also known as the activity series, is a list of metals arranged according to their standard electrode potentials. A metal’s position in the series predicts its ability to be oxidized or reduced. Metals higher in the series, like aluminum, are more likely to be oxidized and hence are more reactive than those lower in the series, such as silver.In the exercise, when a tarnished silver spoon is placed in contact with a reactive metal and immersed in a boiling baking soda solution, it's the relative positions of these metals in the electrochemical series that determine the direction of the redox reaction. Aluminum, being higher than silver in the series, donates electrons to the silver ions in the tarnish, causing the silver ions to become reduced to elemental silver.The electrochemical series also explains the claim that the product, likely composed of aluminum, will never need to be replaced. While aluminum can theoretically be used multiple times, it will eventually be consumed through continuous reactions. However, due to its low cost and abundant nature, aluminum is often considered a disposable reagent in this process.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

$$E_{\text {cathode }}^{\circ}=(2.71-2.310) V=+0.40 V$$VVV

Of the following statements concerning electrochemical cells, the correct ones are: (a) The cathode is the negative electrode in both voltaic and electrolytic cells. (b) The function of a salt bridge is to permit the migration of electrons between the half-cell compartments of an electrochemical cell. (c) The anode is the negative electrode in a voltaic cell. (d) Electrons leave the cell from either the cathode or the anode, depending on what electrodes are used. (e) Reduction occurs at the cathode in both voltaic and electrolytic cells. (f) If electric current is drawn from a voltaic cell long enough, the cell becomes an electrolytic cell. (g) The cell reaction is an oxidationreduction reaction.

Consider the reaction \(\operatorname{Co}(\mathrm{s})+\mathrm{Ni}^{2+}(\mathrm{aq}) \longrightarrow\) \(\mathrm{Co}^{2+}(\mathrm{aq})+\mathrm{Ni}(\mathrm{s}), \quad\) with \(\quad E_{\mathrm{cell}}^{\circ}=0.02 \mathrm{V} . \quad\) If \(\quad \mathrm{Co}(\mathrm{s}) \quad\) is added to a solution with \(\left[\mathrm{Ni}^{2+}\right]=1 \mathrm{M},\) should the reaction go to completion? Explain.

The following voltaic cell registers an \(E_{\text {cell }}=0.108 \mathrm{V}\) What is the pH of the unknown solution? $$\operatorname{Pt}\left|\mathrm{H}_{2}(\mathrm{g}, 1 \mathrm{atm})\right| \mathrm{H}^{+}(x \mathrm{M}) \| \mathrm{H}^{+}(1.00 \mathrm{M}) |$$ $$\mathrm{H}_{2}(\mathrm{g}, 1 \mathrm{atm}) | \mathrm{Pt}$$

For the reaction \(\operatorname{Co}(\mathrm{s})+\mathrm{Ni}^{2+}(\mathrm{aq}) \longrightarrow \mathrm{Co}^{2+}(\mathrm{aq})+\) \(\mathrm{Ni}(\mathrm{s}), E_{\mathrm{cell}}^{\circ}=0.03 \mathrm{V} .\) If cobalt metal is added to an aqueous solution in which \(\left[\mathrm{Ni}^{2+}\right]=1.0 \mathrm{M},\) (a) the reaction will not proceed in the forward direction at all; (b) the displacement of \(\mathrm{Ni}(\mathrm{s})\) from the \(\mathrm{Ni}^{2+}(\mathrm{aq})\) will go to completion; (c) the displacement of \(\mathrm{Ni}(\mathrm{s})\) from the solution will proceed to a considerable extent, but the reaction will not go to completion; (d) there is no way to predict how far the reaction will proceed.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free