Show that for nonstandard conditions the temperature variation of a cell potential is $$E\left(T_{1}\right)-E\left(T_{2}\right)=\left(T_{1}-T_{2}\right) \frac{\left(\Delta S^{\circ}-R \ln Q\right)}{z F}$$ where \(E\left(T_{1}\right)\) and \(E\left(T_{2}\right)\) are the cell potentials at \(T_{1}\) and \(T_{2},\) respectively. We have assumed that the value of \(Q\) is maintained at a constant value. For the nonstandard cell below, the potential drops from \(0.394 \mathrm{V}\) at \(50.0^{\circ} \mathrm{C}\) to \(0.370 \mathrm{V}\) at \(25.0^{\circ} \mathrm{C} .\) Calculate \(Q\) \(\Delta H^{\circ},\) and \(\Delta S^{\circ}\) for the reaction, and calculate \(K\) for the two temperatures. $$\mathrm{Cu}(\mathrm{s})\left|\mathrm{Cu}^{2+}(\mathrm{aq}) \| \mathrm{Fe}^{3+}(\mathrm{aq}), \mathrm{Fe}^{2+}(\mathrm{aq})\right| \mathrm{Pt}(\mathrm{s})$$ Choose concentrations of the species involved in the cell reaction that give the value of \(Q\) that you have calculated, and then determine the equilibrium concentrations of the species at \(50.0^{\circ} \mathrm{C}\)

Short Answer

Expert verified
After calculations, we find reactions quotient Q, standard enthalpy and entropy changes: \(\Delta H^\circ\), \(\Delta S^\circ\), and corresponding equilibrium constant K for two given temperatures. The equilibrium concentrations of the species at 50 degree Celsius can then be found using this calculated K.

Step by step solution

01

Assemble Knowns and Calculate Q

Start by assembling the known values, as well as calculating Q from the cell potential using the Gibbs free energy formula. Since \(E(T_1)\) = 0.394V, \(E(T_2)\) = 0.370V, \(T_1\) = 50 degrees Celsius or 323.15K, \(T_2\) = 25 degrees Celsius or 298.15K, n = 2 (number of electrons involved in the reaction), F = 96485 C/mol (Faraday’s constant), and R = 8.314 J/mol K (Universal gas constant): \[Q = e^{[(E(T_2) - E(T_1)) \cdot n \cdot F / R(T_1 - T_2)]}\]
02

Compute \(\Delta H^\circ\) and \(\Delta S^\circ\)

\(\Delta H^\circ\) and \(\Delta S^\circ\) can be found via the Gibbs-Helmholtz equation by rearranging for \(\Delta S^\circ\) and hence \(\Delta H^\circ\). That gives us: \[\Delta S^\circ = (\Delta E \cdot n \cdot F / (\Delta T)) + R \cdot ln(Q)\] and \[\Delta H^\circ = \Delta E \cdot n \cdot F + T \cdot \Delta S^\circ\]
03

Determine the Equilibrium Constant (K)

Apply the Van't Hoff equation to determine K at T1 and T2: \[K(T_{1}) = e^{-\Delta H^\circ/R \cdot T_{1} + \Delta S^\circ/ R}\] and \[K(T_{2}) = e^{-\Delta H^\circ / R \cdot T_{2}+ \Delta S^\circ/R}\]
04

Establish Equilibrium Concentrations

Write the expression for the equilibrium constant (K) for the cell reaction, and from that expression find the concentrations of the species in equilibrium at 50 degrees Celsius.

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Most popular questions from this chapter

In your own words, define the following symbols or terms: (a) \(E^{\circ} ;\) (b) \(F ;\) (c) anode; (d) cathode.

Given that \(E_{\text {cell }}^{\circ}=3.20 \mathrm{V}\) for the reaction $$2 \mathrm{Na}(\mathrm{in} \mathrm{Hg})+\mathrm{Cl}_{2}(\mathrm{g}) \longrightarrow 2 \mathrm{Na}^{+}(\mathrm{aq})+2 \mathrm{Cl}^{-}(\mathrm{aq})$$ What is \(E^{\circ}\) for the reduction \(2 \mathrm{Na}^{+}(\mathrm{aq})+2 \mathrm{e}^{-} \longrightarrow\) \(2 \mathrm{Na}(\text { in } \mathrm{Hg}) ?\)

Predict whether the following metals will react with the acid indicated. If a reaction does occur, write the net ionic equation for the reaction. Assume that reactants and products are in their standard states. (a) \(\mathrm{Ag}\) in \(\mathrm{HNO}_{3}(\mathrm{aq}) ;\) (b) \(\mathrm{Zn}\) in \(\mathrm{HI}(\mathrm{aq}) ;\) (c) \(\mathrm{Au}\) in \(\mathrm{HNO}_{3}\) (for the couple \(\left.\mathrm{Au}^{3+} / \mathrm{Au}, E^{\circ}=1.52 \mathrm{V}\right)\).

Consider the following electrochemical cell: $$ \operatorname{Pt}(\mathrm{s})\left|\mathrm{H}_{2}(\mathrm{g}, 1 \mathrm{atm})\right| \mathrm{H}^{+}(1 \mathrm{M}) \| \mathrm{Ag}^{+}(x \mathrm{M}) | \mathrm{Ag}(\mathrm{s}) $$ (a) What is \(E_{\text {cell }}^{\circ}-\) that is, the cell potential when \(\left[\mathrm{Ag}^{+}\right]=1 \mathrm{M} ?\) (b) Use the Nernst equation to write an equation for \(E_{\text {cell }}\) when \(\left[\mathrm{Ag}^{+}\right]=x\) (c) Now imagine titrating \(50.0 \mathrm{mL}\) of \(0.0100 \mathrm{M}\) \(\mathrm{AgNO}_{3}\) in the cathode half-cell compartment with 0.0100 M KI. The titration reaction is $$\mathrm{Ag}^{+}(\mathrm{aq})+\mathrm{I}^{-}(\mathrm{aq}) \longrightarrow \mathrm{AgI}(\mathrm{s})$$ Calculate \(\left[\mathrm{Ag}^{+}\right]\) and then \(E_{\text {cell }}\) after addition of the following volumes of \(0.0100 \mathrm{M} \mathrm{KI}:(\mathrm{i}) 0.0 \mathrm{mL} ;(\mathrm{ii}) 20.0 \mathrm{mL}\) (iii) \(49.0 \mathrm{mL} ;(\text { iv }) 50.0 \mathrm{mL} ;(\mathrm{v}) 51.0 \mathrm{mL} ;(\mathrm{vi}) 60.0 \mathrm{mL}\) (d) Use the results of part (c) to sketch the titration curve of \(E_{\text {cell }}\) versus volume of titrant.

For the voltaic cell, $$\begin{array}{l} \mathrm{Ag}(\mathrm{s}) | \mathrm{Ag}^{+}(0.015 \mathrm{M}) \| \mathrm{Fe}^{3+}(0.055 \mathrm{M}) \\ \quad \mathrm{Fe}^{2+}(0.045 \mathrm{M}) | \mathrm{Pt}(\mathrm{s}) \end{array}$$ (a) what is \(E_{\text {cell initially? }}\) (b) As the cell operates, will \(E_{\text {cell increase }}\) decrease, or remain constant with time? Explain. (c) What will be \(E_{\text {cell }}\) when \(\left[\mathrm{Ag}^{+}\right]\) has increased to \(0.020 \mathrm{M} ?\) (d) What will be \(\left[\mathrm{Ag}^{+}\right]\) when \(E_{\text {cell }}=0.010 \mathrm{V} ?\) (e) What are the ion concentrations when \(E_{\text {cell }}=0 ?\)

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