To displace \(\mathrm{Br}_{2}\) from an aqueous solution of \(\mathrm{Br}^{-}\) add \((\mathrm{a}) \mathrm{I}_{2}(\mathrm{aq}) ;\) (b) \(\mathrm{Cl}_{2}(\mathrm{aq}) ;\) (c) \(\mathrm{H}_{2}(\mathrm{g}) ;\) (d) \(\mathrm{Cl}^{-}(\mathrm{aq})\) (e) \(\mathrm{I}_{3}^{-}(\mathrm{aq})\).

Short Answer

Expert verified
The Chlorine (\(Cl_{2}\)) can displace the Bromine (\(Br_{2}\)) from its aqueous solution, while other given chemicals (Iodine, Hydrogen, Chloride ion, and Triiodide ion) cannot.

Step by step solution

01

Analyze Each Chemical

This involves looking at each chemical in the list and determining its position in the reactivity series of halogens.
02

Predict the Possibility of each Displacement

If a halogen in the list is more reactive than the Bromine in the aqueous solution (i.e., it is higher in the reactivity series), it can displace the Bromine. Otherwise, it cannot displace the Bromine.
03

Summarize Results

(a) Iodine (\(I_2\)): Iodine is less reactive than Bromine; no displacement will occur. (b) Chlorine (\(Cl_2\)): Chlorine is more reactive than Bromine and will displace the Bromine to form \(Br_{2}\). (c) Hydrogen (\(H_2\)): Hydrogen does not belong to the halogen group and doesn't displace Bromine from its aqueous solution. (d) Chloride ion (\(Cl^{-}\)): even though \(Cl_2\) is more reactive, ions generally do not participate in such displacement reactions. (e) Triiodide ion (\(I_{3}^{-}\)): Iodine is less reactive than Bromine, so there will be no displacement.

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