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Chapter 22: Problem 134

What is the acid anhydride of \((a) \mathrm{H}_{2} \mathrm{SO}_{4} ;(\mathrm{b}) \mathrm{H}_{2} \mathrm{SO}_{3}\) (c) \(\mathrm{HClO}_{4} ;\) (d) \(\mathrm{HIO}_{3}\) ?

Short Answer

Expert verified
The acid anhydrides are: (a) \(H_{2}S_{2}O_{7}\), (b) \(H_{2}S_{2}O_{5}\), (c) none, (d) none.

Step by step solution

01

Find the Acid Anhydride of \(H_{2}SO_{4}\)

Start by taking two moles of \(H_{2}SO_{4}\) and remove one water (\(H_{2}O\)). Let's write the reaction as \(2 H_{2}SO_{4} -> Anhydride + H_2O\). The anhydride for \(H_{2}SO_{4}\) will be \(H_{2}S_{2}O_{7}\).
02

Find the Acid Anhydride of \(H_{2}SO_{3}\)

In a similar way for \(H_{2}SO_{3}\), remove one water from two moles of the acid. So the equation looks like this: \(2 H_{2}SO_{3} -> Anhydride + H_2O\). The anhydride for \(H_{2}SO_{3}\) will be \(H_{2}S_{2}O_{5}\).
03

Find the Acid Anhydride of \(HClO_{4}\)

For \( HClO_{4}\), as it's based on a single atom central element (Chlorine), it typically won't form an anhydride. The removal of water from two moles of this substance is not possible. So, no anhydride for \(HClO_{4}\).
04

Find the Acid Anhydride of \(HIO_{3}\)

Meanwhile for \(HIO_{3}\), it's similar to \(HClO_{4}\). Being based on single atom central element (Iodine), it cannot form an anhydride by losing water from two moles. Therefore, no anhydride for \(HIO_{3}\).

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Most popular questions from this chapter

Despite the fact that it has the higher molecular mass, XeO \(_{4}\) exists as a gas at \(298 \mathrm{K},\) whereas \(\mathrm{XeO}_{3}\) is a solid. Give a plausible explanation for this observation.

The bond energies of \(\mathrm{Cl}_{2}\) and \(\mathrm{F}_{2}\) are 243 and \(159 \mathrm{kJ} \mathrm{mol}^{-1},\) respectively. Use these data to explain why \(\mathrm{XeF}_{2}\) is a much more stable compound than \(\mathrm{XeCl}_{2} .[\text { Hint: Recall that Xe exists as a monatomic gas. }]\).

Draw plausible Lewis structures for (a) dimethylhydrazine, \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NNH}_{2}\) (b) nitryl chloride, \(\mathrm{ClNO}_{2}\) (Central atom is \(\mathrm{N}\) ) (c) phosphorous acid, a diprotic acid with the empirical formula \(\mathrm{H}_{3} \mathrm{PO}_{3}\).

Write chemical equations for the following reactions: (a) the displacement of \(\mathrm{H}_{2}(\mathrm{g})\) from \(\mathrm{HCl}(\mathrm{aq})\) by \(\mathrm{Al}(\mathrm{s})\) (b) the re-forming of propane gas \(\left(\mathrm{C}_{3} \mathrm{H}_{8}\right)\) with steam (c) the reduction of \(\mathrm{MnO}_{2}(\mathrm{s})\) to \(\mathrm{Mn}(\mathrm{s})\) with \(\mathrm{H}_{2}(\mathrm{g})\)

Provide an explanation for the observation that helium, neon, and argon do not react directly with fluorine.
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