Show by calculation whether the disproportionation of chlorine gas to chlorate and chloride ions will occur under standard-state conditions in an acidic solution.

Short Answer

Expert verified
The disproportionation of chlorine gas to chlorate and chloride ions will not occur under standard-state conditions in an acidic solution since the value of E˚Cell is negative (-0.11 V).

Step by step solution

01

Write Half-Reactions

Separate the overall redox reaction into two half-reactions. Chlorine is both oxidized and reduced in this process, forming chloride and chlorate ions. The half reactions are: \n 1. \(Cl2(g) + 2e^- ⟶ 2Cl^-(aq)\) (Reduction)\n 2. \(Cl2(g) + 6H2O (l) ⟶ 2ClO3^-(aq) + 12H^+ (aq) + 10e^-\) (Oxidation)
02

Determine the Reduction Potential

The standard reduction potential, E˚, can be obtained from standard reduction tables for each of the half-reactions. These are: \n 1. E˚(Cl2/Cl-) = +1.36 V \n 2. E˚(Cl2/ClO3-) = +1.47 V
03

Apply the Nernst Equation

According to the Nernst equation, the overall cell potential, E˚cell, is calculated as follows: \( E˚cell = E˚(Reduction) - E˚(Oxidation) \). Since chlorine is being reduced to chloride and oxidized to chlorate, we substitute the corresponding E˚s. \( E˚Cell = E˚(Cl2/Cl-) - E˚(Cl2/ClO3-) = +1.36 V - (+1.47 V)\
04

Determine Spontaneity of Reaction

The sign of E˚Cell tells us whether the reaction is spontaneous or not. A positive E˚Cell indicates a spontaneous redox reaction, while a negative E˚Cell indicates a non-spontaneous redox reaction. Hence, calculate E˚Cell. If our calculated E˚Cell is less than 0; the reaction is not spontaneous under standard conditions.

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