In the metallurgical extraction of silver and gold, an alloy of the two metals is often obtained. The alloy can be separated into Ag and Au either with concentrated \(\mathrm{HNO}_{3}\) or boiling concentrated \(\mathrm{H}_{2} \mathrm{SO}_{4},\) in a process called parting. Write chemical equations to show how these separations work.

Short Answer

Expert verified
1. Reaction of Ag and Au with Nitric Acid: \(3Ag + 4HNO3 -> 3AgNO3 + NO + 2H2O\) and \(Au + HNO3 -> Au + HNO3\). 2. Reaction of AgNO3 with Water: \(3AgNO3+ 3H2O -> 3Ag + 4NO + 6H2O\). 3. Reaction of Ag and Au with Sulphuric Acid: \(2Ag + H2SO4 -> Ag2SO4 +SO2 +2H2O\) and \(Au + H2SO4 -> Au + H2SO4\).

Step by step solution

01

Reaction of Ag and Au with Nitric Acid

When Ag and Au react with nitric acid, the nitric acid oxidizes Ag to Ag+ and Au remains unaffected due to its low reactivity. The reaction can be written as follows: \(3Ag + 4HNO_3 -> 3AgNO_3 + NO + 2H_2O\) and \(Au + HNO_3 -> Au + HNO_3\) (No reaction takes place)
02

Reaction of AgNO3 with Water

The silver nitrate formed in the first step will further react with water to form silver, nitric oxide and water. The reaction can be written as follows: \(3AgNO3+ 3H2O -> 3Ag + 4NO + 6H2O\)
03

Reaction of Ag and Au with Sulphuric Acid

When the alloy is reacted with hot concentrated sulphuric acid, the silver from the alloy reacts with the sulphuric acid to produce silver sulfate and SO2, while gold again remains unaffected. The reaction can be written as follows: \(2Ag + H2SO4 -> Ag2SO4 +SO2 +2H2O\) and \(Au + H2SO4 -> Au + H2SO4\) (No reaction takes place)

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