The only diamagnetic ion of the following group is (a) \(\mathrm{Cr}^{2+} ;\) (b) \(\mathrm{Zn}^{2+} ;\) (c) \(\mathrm{Fe}^{3+} ;\) (d) \(\mathrm{Ag}^{2+} ;\) (e) \(\mathrm{Ti}^{3+}\).

Short Answer

Expert verified
The only diamagnetic ion out of the given groups is \(\mathrm{Zn}^{2+}\)

Step by step solution

01

Understand the electronic configuration of Ions

Know the electronic configuration of given ions. An ion is diamagnetic if it does not have any unpaired electrons in its outer shell. Thus, we have to identify the ion with all paired electrons.
02

Analyze each given ion

Analyze each ion: Chromium ion \(\mathrm{Cr}^{2+}\) has configuration [Ar] 3d4. Zinc ion \(\mathrm{Zn}^{2+}\) has configuration [Ar] 3d10. Iron ion \(\mathrm{Fe}^{3+}\) has configuration [Ar] 3d5. Silver ion \(\mathrm{Ag}^{2+}\) has configuration [Kr] 4d8. Titanium ion \(\mathrm{Ti}^{3+}\) has configuration [Ar] 3d1.
03

Identify the diamagnetic ion

From the configurations given above, only zinc ion \(\mathrm{Zn}^{2+}\) has all paired electrons. It has no unpaired electrons in its outer shell. Therefore, out of the given ions, \(\mathrm{Zn}^{2+}\) is diamagnetic.

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