Write equations to represent the following observations. (a) A quantity of \(\mathrm{CuCl}_{2}(\mathrm{s})\) is dissolved in concentrated HCl(aq) and produces a yellow solution. The solution is diluted to twice its volume with water and assumes a green color. On dilution to ten times its original volume, the solution becomes pale blue. (b) When chromium metal is dissolved in \(\mathrm{HCl}(\mathrm{aq}), \mathrm{a}\) blue solution is produced that quickly turns green. Later the green solution becomes blue-green and then violet.

Short Answer

Expert verified
The chemical equations representing the reactions are: \n(a) \n1. \( \mathrm{CuCl}_{2}(\mathrm{s}) + 2\mathrm{HCl}(\mathrm{aq}) \rightleftharpoons [CuCl4]^{2-}(\mathrm{aq}) + 2H^+(\mathrm{aq}) \)\n2. \([CuCl4]^{2-}(aq) \rightleftharpoons Cu^{2+}(aq) + 4Cl^-(aq)\) and \(Cu^{2+}(aq) + 4H2O(l) \rightarrow [Cu(H2O)4]^{2+}(aq)\) \n(b) \n1. \(\mathrm{Cr(s)}+ 2\mathrm{HCl(aq)} \rightarrow \mathrm{CrCl2(aq)} + \mathrm{H2(g)}\)\n2. \(\mathrm{Cr^{2+}(s)}+ \mathrm{6H2O(l)} \rightarrow [\mathrm{Cr(H2O)6}]^{2+}(aq)\)\n3. \([\mathrm{Cr(H2O)6}]^{2+}(aq) + 2 \mathrm{H2O(l)} \leftrightarrow [\mathrm{Cr(H2O)4(OH)2}]^{+}(aq) + 4 \mathrm{H2O(l)}\) and \n4. \([\mathrm{Cr(H2O)4(OH)2}]^{+}(aq) \rightarrow [\mathrm{Cr(H2O)3(OH)3]\)

Step by step solution

01

Formation of CuCl2 Complex Ion

Copper (II) chloride reacts with hydrochloric acid to form a CuCl4 complex ion which gives the solution a yellow color. This equilibrium process can be represented by the equation: \n\( \mathrm{CuCl}_{2}(\mathrm{s}) + 2\mathrm{HCl}(\mathrm{aq}) \rightleftharpoons [CuCl4]^{2-}(\mathrm{aq}) + 2H^+(\mathrm{aq}) \)
02

Dilution and color change of CuCl2 Complex Ion

When the yellow solution of [CuCl4]2- complex is diluted, the equilibrium is disturbed and shifts back towards reactants according to Le Chatelier’s principle, producing Cu(H2O)4 complex ion. This change of complex ion through dilution leads to the change of the solution color, which can be represented by the following equation: \n\([CuCl4]^{2-}(aq) \rightleftharpoons Cu^{2+}(aq) + 4Cl^-(aq)\) followed by \(Cu^{2+}(aq) + 4H2O(l) \rightarrow [Cu(H2O)4]^{2+}(aq)\)
03

Reaction of Chromium in Hydrochloric Acid

When chromium metal reacts with hydrochloric acid, the chromium is oxidized to Cr2+ with the release of hydrogen gas. This can be represented by the equation: \n\(\mathrm{Cr(s)}+ 2\mathrm{HCl(aq)} \rightarrow \mathrm{CrCl2(aq)} + \mathrm{H2(g)}\)
04

Formation and change of Chromium Complex Ions

The Cr2+ ion in solution readily reacts with water to form a series of coordination complexes that are responsible for the color changes observed. The main reactions are: \n\(\mathrm{Cr^{2+}(s)}+ \mathrm{6H2O(l)} \rightarrow [\mathrm{Cr(H2O)6}]^{2+}(aq)\) (which is blue), and \n\([\mathrm{Cr(H2O)6}]^{2+}(aq) + 2 \mathrm{H2O(l)} \leftrightarrow [\mathrm{Cr(H2O)4(OH)2}]^{+}(aq) + 4 \mathrm{H2O(l)}\) (which is green) and \n\([\mathrm{Cr(H2O)4(OH)2}]^{+}(aq) \rightarrow [\mathrm{Cr(H2O)3(OH)3]\) (aqua color) which eventually becomes violet as [\mathrm{Cr(H2O)3(OH)3}] decomposes.

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Most popular questions from this chapter

Of the following complex ions, the one that is optically active is (a) \(\operatorname{cis}-\left[\operatorname{CoCl}_{2}(\text { en })_{2}\right]^{+} ;\) (b) \(\left[\operatorname{CoCl}_{2}\left(\mathrm{NH}_{3}\right)_{4}\right]^{+}\) (c) \(\left[\mathrm{CoCl}_{4}\left(\mathrm{NH}_{3}\right)_{2}\right]^{-} ;(\mathrm{d})\left[\mathrm{CuCl}_{4}\right]^{-}\).

Write a series of equations to show the stepwise displacement of \(\mathrm{H}_{2} \mathrm{O}\) ligands in \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) by ethylenediamine, for which \(\log K_{1}=4.34, \log K_{2}=3.31\), and \(\log K_{3}=2.05 .\) What is the overall formation constant, \(\beta_{3}=K_{f},\) for \(\left[\mathrm{Fe}(\mathrm{en})_{3}\right]^{3+} ?\)

In both \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\) and \(\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4-}\) ions, the iron is present as \(\mathrm{Fe}(\mathrm{II}) ;\) however, \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\) is paramagnetic, whereas \(\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4-}\) is diamagnetic. Explain this difference.

The amino acid glycine \(\left(\mathrm{NH}_{2} \mathrm{CH}_{2} \mathrm{CO}_{2} \mathrm{H}\right.,\) denoted Hgly) binds as an anion and is a bidentate ligand. Draw and name all possible isomers of \(\left[\mathrm{Co}(\mathrm{gly})_{3}\right]\) How many isomers are possible for the compound $$\left[\mathrm{Co}(\mathrm{gly})_{2} \mathrm{Cl}\left(\mathrm{NH}_{3}\right)\right]\left[\text {Hint:} \mathrm{NH}_{2} \mathrm{CH}_{2} \mathrm{CO}_{2}^{-}\text {is }\right.$$ the glycinate anion.]

The most soluble of the following solids in \(\mathrm{NH}_{3}(\mathrm{aq})\) is (a) \(\mathrm{Ca}(\mathrm{OH})_{2} ;\) (b) \(\mathrm{Cu}(\mathrm{OH})_{2} ;\) (c) \(\mathrm{BaSO}_{4} ;\) (d) \(\mathrm{MgCO}_{3}\) (e) \(\overline{\mathrm{Fe}_{2} \mathrm{O}_{3}}\).

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