Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 24: Problem 5

Draw Lewis structures for the following ligands: (a) \(\mathrm{H}_{2} \mathrm{O} ;\) (b) \(\mathrm{CH}_{3} \mathrm{NH}_{2} ;\) (c) \(\mathrm{ONO}^{-} ;\) (d) SCN \(^{-}\).

Short Answer

Expert verified
The Lewis structures for these ligands are: (a) H:O:H for H2O, (b) H3C-NH2 for CH3NH2, (c) O=N-O: for ONO-, and (d) S=C=N: for SCN-.

Step by step solution

01

H2O Lewis Structure

Begin with the water molecule. Oxygen atom has 6 valence electrons and each Hydrogen atom has 1 valence electron, for a total of 8 valence electrons. Arrange the atoms as H—O—H, then start using the valence electrons to form bonds and fill the outer shells. The Lewis structure for H2O is: \n H:O:H \n ..
02

CH3NH2 Lewis Structure

Next, draw the structure for CH3NH2. Recall that Carbon has 4, Nitrogen has 5, and Hydrogen has 1 valence electron. Since there are three Hydrogens bound to one Carbon and two Hydrogens bound to the Nitrogen, the total valence electrons would be equal to 14. One way to draw the structure would be: H3C-NH2, where each dash represents a pair of shared electrons.
03

ONO- Lewis Structure

In the ONO- molecule, there is 1 extra electron due to the negative charge. So Oxygen has 6, Nitrogen has 5, and plus the extra electron, gives a total of 18 electrons. The structure can be drawn like this: O=N-O:, where the last Oxygen atom has three pairs of lone electrons.
04

SCN- Lewis Structure

Finally, in the SCN- molecule, Carbon has 4, Sulfur has 6, and Nitrogen has 5 valence electrons; and again, there is 1 extra electron due to the negative charge. Hence, the total number of valence electrons is 16. The structure is best represented as: S=C=N:, where both Sulfur and Nitrogen atoms have two pairs of lone electrons and Carbon has no lone pairs.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Show that the oxidation of \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}\) to \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}\) referred to on page 1098 should occur spontaneously in alkaline solution with \(\mathrm{H}_{2} \mathrm{O}_{2}\) as an oxidizing agent.

Briefly describe each of the following ideas, phenomena, or methods: (a) spectrochemical series; (b) crystal field theory; (c) optical isomer; (d) structural isomerism.

Of the following, the one that is a Bronsted-Lowry acid is (a) \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+} ;\) (b) \(\left[\mathrm{FeCl}_{4}\right]^{-} ;\) (c) \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) (d) \(\left[\mathrm{Zn}(\mathrm{OH})_{4}\right]^{-}\).

Provide a valence bond description of the bonding in the \(\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{6}^{3+}\) ion. According to the valence bond description, how many unpaired electrons are there in the \(\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{6}^{3+}\) complex? How does this prediction compare with that of crystal field theory?

Verify the statement on page 1101 that neither \(\mathrm{Ca}^{2+}\) nor \(\mathrm{Mg}^{2+}\) found in natural waters is likely to precipitate from the water on the addition of other reagents if the ions are complexed with EDTA. Assume reasonable values for the total metal ion concentration and that of free EDTA, such as \(0.10 \mathrm{M}\) each.
See all solutions

Recommended explanations on Chemistry Textbooks

Organic Chemistry

Read Explanation

Chemical Analysis

Read Explanation

The Earths Atmosphere

Read Explanation

Physical Chemistry

Read Explanation

Kinetics

Read Explanation

Chemical Reactions

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free