Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 25: Problem 18

Another possible nuclear reaction leading to the formation of element-120 is between uranium-238 and nickel-64. Write a nuclear equation for this nuclear reaction.

Short Answer

Expert verified
The nuclear reaction between Uranium-238 and Nickel-64 leading to the formation of element-120 is expressed in the nuclear equation as \( \text{{^238_92U}} + \text{{^64_28Ni}} \rightarrow \text{{^302_120Element}} + 2\text{{^1_0n}} \).

Step by step solution

01

Understand the given

Here, uranium-238 and nickel-64 are used, so uranium (U) has an atomic number of 92 and a mass number of 238 while Nickel (Ni) has an atomic number of 28 and a mass number of 64.
02

Apply the conservation law

When two atomic nuclei combine, their atomic numbers and mass numbers are separately conserved. This means the sum of the atomic numbers on the left of the equation should equal the sum of atomic numbers on the right. The same applies to mass numbers.
03

Write the nuclear equation

Write down the elements and their atomic and mass numbers. For uranium-238 and nickel-64, following the conservation law will result: \[ \text{{Uranium-238}} + \text{{Nickel-64}} \rightarrow \text{{Element-120}} + x\] Where we need to find out what x will be.
04

Compute for x

By subtracting the atomic number and mass number of element-120 from the sum of the atomic numbers and mass numbers of Uranium-238 and Nickel-64 respectively, we can compute for x. This will result in two neutrons.
05

Finalize The Nuclear Equation

The final nuclear equation is: \[ \text{{^238_92U}} + \text{{^64_28Ni}} \rightarrow \text{{^302_120Element}} + 2\text{{^1_0n}} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Explain why more energy is released in a fusion process than in a fission process.

Both \(\beta^{-}\) and \(\beta^{+}\) emissions are observed for artificially produced radioisotopes of low atomic numbers, but only \(\beta^{-}\) emission is observed with naturally occurring radioisotopes of high atomic number. Why do you suppose this is so?

Briefly describe each of the following ideas, phenomena, or methods: (a) radioactive decay series;(b) charged-particle accelerator; (c) neutron-to- proton ratio; (d) mass-energy relationship; (e) background radiation.

Write equations for the following nuclear reactions. (a) bombardment of \(^{238} \mathrm{U}\) with \(\alpha\) particles to produce \(^{239} \mathrm{Pu}\) (b) bombardment of tritium ( \(^{3} \mathrm{H}\) ) with \(_{1}^{2} \mathrm{H}\) to produce \(^{4} \mathrm{He}\) (c) bombardment of \(^{33} \mathrm{S}\) with neutrons to produce \(^{33} \mathrm{P}\).

Explain why neutron activation analysis is so useful in identifying trace elements in a sample, in contrast to ordinary methods of quantitative analysis, such as precipitation or titration.
See all solutions

Recommended explanations on Chemistry Textbooks

The Earths Atmosphere

Read Explanation

Inorganic Chemistry

Read Explanation

Chemical Reactions

Read Explanation

Chemistry Branches

Read Explanation

Physical Chemistry

Read Explanation

Ionic and Molecular Compounds

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free