Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 25: Problem 85

Write nuclear equations to represent (a) the decay of \(^{214} \mathrm{Ra}\) by \(\alpha\) -particle emission (b) the decay of \(^{205}\) At by positron emission (c) the decay of \(^{212} \mathrm{Fr}\) by electron capture (d) the reaction of two deuterium nuclei (deuterons) to produce a nucleus of \(\frac{3}{2} \mathrm{He}\). (e) the production of \({243}_{97} \mathrm{Bk}\) get by the \(\alpha\) -particle bombardment of\({241}_{95} \mathrm{Am}\) (f) a nuclear reaction in which thorium-232 is bombarded with \(\alpha\) particles, producing a new nuclide and four neutrons.

Short Answer

Expert verified
The nuclear equations corresponding to the tasks are respectively: \n(a) \(^{214}_{88}\mathrm{Ra} \rightarrow ^{210}_{86}\mathrm{Rn} + ^{4}_{2}\mathrm{He}\), \n(b) \(^{205}_{85}\mathrm{At} \rightarrow ^{205}_{84}\mathrm{Po} + ^{0}_{1}\mathrm{e^{+}}\), \n(c) \(^{212}_{87}\mathrm{Fr} + ^{0}_{-1}\mathrm{e^-} \rightarrow^{212}_{86}\mathrm{Rn}\), \n(d) \(^{2}_{1}\mathrm{H} + ^{2}_{1}\mathrm{H} \rightarrow ^{3}_{2}\mathrm{He} + ^{1}_{0}\mathrm{n}\), \n(e) \(^{241}_{95}\mathrm{Am} + ^{4}_{2}\mathrm{He} \rightarrow^{245}_{97}\mathrm{Bk}\) and \n(f) \(^{232}_{90}\mathrm{Th} + ^{4}_{2}\mathrm{He} \rightarrow^{232}_{92}\mathrm{U} + 4^{1}_{0}\mathrm{n}\).

Step by step solution

01

Nuclear equation for alpha decay of Radon-214

In alpha decay, an alpha particle, which is a helium nucleus (\(^{4}_2\mathrm{He}\)), is emitted. Therefore, the original nucleus loses 2 protons and 2 neutrons. The equation for this reaction is \(^{214}_{88}\mathrm{Ra} \rightarrow ^{210}_{86}\mathrm{Rn} + ^{4}_{2}\mathrm{He}\).
02

Nuclear equation for positron emission of Astatine-205

In positron emission, a particle with the same mass as an electron but with a positive charge is released. This corresponds to one proton changing into a neutron. The equation for this reaction is \(^{205}_{85}\mathrm{At} \rightarrow ^{205}_{84}\mathrm{Po} + ^{0}_{1}\mathrm{e^{+}}\).
03

Nuclear equation for electron capture by Francium-212

During electron capture, an electron from the electron shell of the atom is captured by the nucleus, converting a proton into a neutron. The equation for this reaction is \(^{212}_{87}\mathrm{Fr} + ^{0}_{-1}\mathrm{e^-} \rightarrow^{212}_{86}\mathrm{Rn}\).
04

Nuclear equation for Deuteron-Deuteron Fusion

In a fusion reaction, two or more smaller nuclei combine to form a larger nucleus. The equation for this reaction is \(^{2}_{1}\mathrm{H} + ^{2}_{1}\mathrm{H} \rightarrow ^{3}_{2}\mathrm{He} + ^{1}_{0}\mathrm{n}\).
05

Nuclear equation for Alpha-particle bombardment of Americium-241

In a reaction with alpha particle bombardment, the target nucleus absorbs the alpha particle. The equation for this reaction is \(^{241}_{95}\mathrm{Am} + ^{4}_{2}\mathrm{He} \rightarrow^{245}_{97}\mathrm{Bk}\).
06

Nuclear equation for a nuclear reaction with Thorium-232

The equation for this reaction (where Thorium-232 is bombarded with an alpha particle, producing a new nuclide and four neutrons) is \(^{232}_{90}\mathrm{Th} + ^{4}_{2}\mathrm{He} \rightarrow^{232}_{92}\mathrm{U} + 4^{1}_{0}\mathrm{n}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A process that produces a one-unit increase in atomic number is (a) electron capture; (b) \(\beta^{-}\) emission;(c) \(\alpha\) emission; (d) \(\gamma\) -ray emission.

Which of the following types of radiation is deflected in a magnetic field? (a) \(X\) ray; (b) \(\gamma\) ray; (c) \(\beta\) ray; (d) neutrons.

Write nuclear equations to represent the formation of an isotope of element 111 with a mass number of 272 by the bombardment of bismuth-209 by nickel-64 nuclei, followed by a succession of five \(\alpha\) -particle emissions.

Supply the missing information in each of the following nuclear equations representing a radioactive decay process.(a) \(160_?\mathrm{W} \longrightarrow\\{\mathrm{Hf}+?\) (b) \(38_? \mathrm{Cl} \longrightarrow_{?}^{?} \mathrm{Ar}+?\) (c) \(^{214} ? \longrightarrow_{?}^{?} \mathrm{Po}+_{-1}^{0} \boldsymbol{\beta}\) (d) \(_{17}^{32} \mathrm{Cl} \longrightarrow_{1}^{?} ?+?\)

Element-120 is located in a region of the neutron versus proton map known as the island of stability. Write a nuclear equation for the generation of element- 120 by bombarding iron isotopes on a plutonium target.
See all solutions

Recommended explanations on Chemistry Textbooks

Chemistry Branches

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Kinetics

Read Explanation

Nuclear Chemistry

Read Explanation

Chemical Analysis

Read Explanation

Organic Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free