Give the isomers of the carboxylic acid with the molecular formula \(\mathrm{C}_{4} \mathrm{H}_{8} \mathrm{O}_{2}\).

Short Answer

Expert verified
The two isomers are butanoic acid and methyl propanoate.

Step by step solution

01

Identify the main functional group and core structure

A carboxylic acid has a -COOH functional group. With 4 carbons in the molecular formula, first consider a straight-chain structure with the carboxylic acid at one end.
02

Experiment with Different Arrangements

Next, experiment with arranging the functional group in different places along this skeleton. Because a carboxylic acid functional group must be at the end of a chain, this functional group could also be located in the second carbon atom from the end.
03

Identify Isomers

Results in two isomers: \[ \begin{array}{ll} 1) & \text { Butanoic acid: }-\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{COOH} \ 2) & \text { Methyl propanoate: }-\mathrm{CH}_{3}-\mathrm{CH}-\left(\mathrm{CH}_{3}\right)-\mathrm{COOH} \end{array}\] Note: Isomers also be cyclical in structure, but for a carboxylic acid with only four carbon atoms, a cyclic structure is not possible.

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