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Chapter 26: Problem 34

Draw a condensed structure to correspond to each of the following names. (a) methylbutane; (b) cyclohexene; (c) 2 -methyl- 3 -hexyne; (d) 2 -butanol; (e) ethyl isopropyl ether; (f) propanal

Short Answer

Expert verified
The condensed structures are (a) Methylbutane: \(\CH_3CH(CH_3)CH_2CH_3\), (b) Cyclohexene: \( \CH_2CH=CHCH_2CH_2CH_2\), (c) 2 -methyl- 3 -hexyne: \( \CH_3CH(C≡C)CH_2CH_2CH_3\), (d) 2 -butanol: \( \CH_3CH(OH)CH_2CH_3\), (e) Ethyl isopropyl ether: \( \CH_3CH_2OCH(CH_3)_2\), (f) Propanal: \( \CH_3CH_2CHO\).

Step by step solution

01

Drawing Methylbutane

Methylbutane consists of a butane chain, which is a four-carbon alkane, and a methyl group located anywhere along the chain except the ends (as this would result in a longer alkane). Thus, the condensed structure is \(\ CH_3CH(CH_3)CH_2CH_3 \).
02

Drawing Cyclohexene

Cyclohexene consists of a hexene ring, which is a six-carbon ring with a double bond. No other groups or parameters are mentioned, so the condensed structure is \(\CH_2CH=CHCH_2CH_2CH_2 \).
03

Drawing 2 -methyl- 3 -hexyne

This compound has a six-carbon chain (hex-) with a triple bond (-yne) at the third carbon and a methyl group (-methyl) at the second carbon. Thus, the condensed structure is \(\CH_3CH(C≡C)CH_2CH_2CH_3 \).
04

Drawing 2 -butanol

This compound consists of a butane chain, which is a four-carbon alkane, with an alcohol group (-ol) at the second carbon. Thus, the condensed structure is \(\CH_3CH(OH)CH_2CH_3 \).
05

Drawing Ethyl isopropyl ether

This compound has an ether function group (an oxygen linked to two alkyl groups) between an ethyl and isopropyl groups. Thus, the condensed structure is \(\CH_3CH_2OCH(CH_3)_2 \).
06

Drawing Propanal

This compound consists of a propane chain, which is a three-carbon alkane, with an aldehyde group (-al) at the end of the chain. Thus, the condensed structure is \(\CH_3CH_2CHO \).

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Most popular questions from this chapter

Give the isomers of the esters having the molecular formula \(\mathrm{C}_{5} \mathrm{H}_{10} \mathrm{O}_{2}\).

Draw the structures of (a) \((E)-3\) -benzyl- 2,5 -dichloro- 4 -methyl- 3 -hexene (b) 1 -ethenyl- 4 -nitrobenzene (c) trans-1-(4-bromophenyl)-2-methylcyclohexane.

A compound with the same hydrogen-to-carbon ratio as cyclobutane is (a) \(\mathrm{C}_{4} \mathrm{H}_{10} ;\) (b) \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CHCH}_{3}\) (c) \(\mathrm{CH}_{3} \mathrm{C}=\mathrm{CCH}_{3} ;\) (d) \(\mathrm{C}_{6} \mathrm{H}_{6}\).

Why is it not necessary to refer to ethene and propene as 1 -ethene and 1 -propene? Can the same be said for butene?

Draw and name all the isomers of (a) \(\mathrm{C}_{6} \mathrm{H}_{14}\) (b) \(\mathrm{C}_{4} \mathrm{H}_{8} ;\) (c) \(\mathrm{C}_{4} \mathrm{H}_{6}\). [Hint: Do not forget double bonds, rings, and combinations of these.].
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