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Chapter 26: Problem 55

Supply a name or structural formula for each of the following. (a) phenylacetylene (b) \(m\) -dichlorobenzene

Short Answer

Expert verified
The chemical structure of Phenylacetylene is represented as \(C_6H_5 - C \equiv CH\). The 'm' in m-Dichlorobenzene stands for meta, meaning the two chlorine atoms are adjacent to each other on the benzene ring, hence it's represented as \(C_6H_4Cl_2\) with the two chlorines at the 1 and 3 positions.

Step by step solution

01

Naming Phenylacetylene

Phenylacetylene is an organic compound that consists of a phenyl group (\(C_6H_5\)), attached to an acetylene (\(C_2H\)) group. The phenyl group is a six-membered aromatic ring, while the acetylene unit consists of a carbon-carbon triple bond. This bond occurs between the phenyl group and one of the carbon atoms of the acetylene.
02

Structural Formula for Phenylacetylene

Start by drawing a six-membered ring for the phenyl group and represent each carbon atom in the ring. Then, draw a carbon-carbon triple bond attached to the ring, representing the acetylene group. The structure should look like this: \[C_6H_5 - C \equiv CH\]. The line connecting the ring and the acetylene group indicates a bond.
03

Naming m-Dichlorobenzene

m-Dichlorobenzene denotes a type of dichlorobenzene where the two chlorine atoms are adjacent to each other on the benzene ring. 'm' stands for meta, which in the context of organic chemistry, signifies that the two chlorines are placed at the 1 and 3 positions on the phenyl group.
04

Structural Formula for m-Dichlorobenzene

To draw the structure, start with a six-membered phenyl ring. Afterward, the two chlorine atoms should be placed in the 1 and 3 positions on the ring, because 'm' stands for 'meta', suggesting they are adjacent. The structure should look like this: \[C_6H_4Cl_2\], with the two chlorines at the 1 and 3 positions.

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Most popular questions from this chapter

Identify the functional group in each compound (i.e., alcohol, amine, etc.). (a) \(\mathrm{CH}_{3} \mathrm{CHBrCH}_{2} \mathrm{CH}_{3}\) (b) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{CHO}\) (c) \(\mathrm{CH}_{3} \mathrm{COCH}_{2} \mathrm{CH}_{3}\) (d) \(\mathrm{C}_{6} \mathrm{H}_{4}(\mathrm{OH})_{2}\).

Draw a structural formula for each of the following compounds. (a) 3 -isopropyloctane; (b) 2 -chloro- 3 -methylpentane; (c) 2 -pentene; (d) dipropyl ether.

Classify the carbon atoms in (a) 2,4 -dimethylpentane, and (b) ethylcyclobutane as methyl, primary \(\left(1^{\circ}\right)\) secondary \(\left(2^{\circ}\right),\) tertiary \(\left(3^{\circ}\right),\) or quaternary \(\left(4^{\circ}\right)\).

Why is it not necessary to refer to ethene and propene as 1 -ethene and 1 -propene? Can the same be said for butene?

Draw as many structural isomers as you can for cyclic ethers (no - OH groups) having the formula \(\mathrm{C}_{4} \mathrm{H}_{6} \mathrm{O}\) Try to draw at least six. (There are more than six.).
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