Write structural formulas for all the isomers of \(\mathrm{C}_{4} \mathrm{H}_{7} \mathrm{Cl}\). Indicate any enantiomers or diastereomers that occur.

Short Answer

Expert verified
There are two structural isomers and two diastereomers for C4H7Cl, resulting in a total of four isomers.

Step by step solution

01

Understanding of the compound

Recognize that the compound C4H7Cl has a total of 4 carbons, 7 hydrogens, and 1 chlorine atom. Now, understand that each carbon atom can form a maximum of four bonds, and these can be with other carbon atoms, hydrogen atoms, or the chlorine atom. The positioning and arrangements of these directly influence isomerism.
02

Structural Isomerism

Now, start to draw the possible structural isomers of C4H7Cl. There are two primary structures. One structure is a straight chain of carbons with the chlorine atom attached to one of the middle carbons. Another one has a branching in the carbon chain with the chlorine atom attached to the branch.
03

Stereoisomerism

Stereoisomerism includes understanding enantiomers and diastereomers. Enantiomers are isomers which are mirror images of each other and cannot be superimposed, while diastereomers are isomers that are not mirror images. Diastereomers can be formed by drawing two or more compounds that are different due to the configuration of the chlorine atom and the hydrogen atom around a carbon atom.
04

Total number of isomers

C4H7Cl has a total number of four isomers: two structural isomers and two diastereomers.

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Most popular questions from this chapter

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Use the half-reaction method to balance the following redox equations. (a) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NO}_{2}+\mathrm{Fe}+\mathrm{H}^{+} \longrightarrow\) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3}^{+}+\mathrm{Fe}^{3+}+\mathrm{H}_{2} \mathrm{O}\) (b) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{OH}+\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}+\mathrm{H}^{+} \longrightarrow\) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CO}_{2} \mathrm{H}+\mathrm{Cr}^{3+}+\mathrm{H}_{2} \mathrm{O}\) (c) \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}_{2}+\mathrm{MnO}_{4}^{-}+\mathrm{H}_{2} \mathrm{O} \longrightarrow\) \(\mathrm{CH}_{3} \mathrm{CHOHCH}_{2} \mathrm{OH}+\mathrm{MnO}_{2}+\mathrm{OH}^{-}\).

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