Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 27: Problem 57

Write the formulas of the products formed from the reaction of propene with each of the following substances: (a) \(\mathrm{H}_{2} ;\) (b) \(\mathrm{Cl}_{2}\); (c) \(\mathrm{HCl} ;\) (d) \(\mathrm{H}_{2} \mathrm{O}\) (in acid).

Short Answer

Expert verified
The products for the reactions are propane, 1,2-dichloropropane, 2-chloropropane, and 2-propanol respectively.

Step by step solution

01

Reaction with Hydrogen

Adding hydrogen in the presence of a catalyst to propene will cause an addition reaction. The hydrogen atoms will add to the carbon atoms of the double bond in a process known as hydrogenation, forming propane \(\mathrm{C}_{3} \mathrm{H}_{8}\).
02

Reaction with Chlorine

Adding chlorine to propene will cause a halogenation reaction. The chlorine atoms will add to the carbon atoms of the double bond, creating 1,2-dichloropropane \(\mathrm{ClCH}_{2}-\mathrm{CHClCH}_{3}\).
03

Reaction with Hydrogen Chloride

The reaction of propene with hydrogen chloride will cause a hydrohalogenation reaction. The molecule will add across the double bond following Markovnikov's rule, which means the hydrogen will add to the carbon with more hydrogen atoms already. As a result, we will get 2-chloropropane \(\mathrm{CH}_{3}-\mathrm{CHClCH}_{3}\).
04

Reaction with Water

The reaction of propene with water, especially under acidic conditions, will cause an hydration reaction. The water molecule will add across the double bond based on Markovnikov's rule. This gives us 2-propanol \(\mathrm{CH}_{3}-\mathrm{CHOHCH}_{3}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Predict the main product(s) of (a) the mononitration of benzoic acid; (b) the monosulfonation of phenol; (c) the monobromination of 2 -nitrobenzaldehyde.

Explain the important distinctions between each pair of terms: (a) base and nucleophile; (b) \(\alpha\) carbon and \(\beta\) carbon; (c) polar protic solvent and polar aprotic solvent; (d) carbocation and radical.

Explain the important distinctions between each pair of terms: (a) nucleophilic substitution and electrophilic aromatic substitution; (b) addition and elimination; (c) \(S_{N} 1\) and \(S_{N} 2 ;\) (d) E1 and E2

Predict the main product(s) of (a) the mononitration of chlorobenzene; (b) the monosulfonation of nitrobenzene; (c) the monochlorination of 1-methyl-2-nitrobenzene

Write the name and structure of the benzene derivatives described below. (a) Formula: \(\mathrm{C}_{8} \mathrm{H}_{10} ;\) forms three monochlorination products when treated with \(\mathrm{Cl}_{2}\) and \(\mathrm{FeCl}_{3}\) (b) Formula: \(\mathrm{C}_{9} \mathrm{H}_{12}\); forms one monochlorination product when treated with \(\mathrm{Cl}_{2}\) and \(\mathrm{FeCl}_{3}\) (c) Formula: \(\mathrm{C}_{9} \mathrm{H}_{12}\); forms four monochlorination products when treated with \(\mathrm{Cl}_{2}\) and \(\mathrm{FeCl}_{3}\)
See all solutions

Recommended explanations on Chemistry Textbooks

Kinetics

Read Explanation

Inorganic Chemistry

Read Explanation

Nuclear Chemistry

Read Explanation

Chemistry Branches

Read Explanation

The Earths Atmosphere

Read Explanation

Making Measurements

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free