Write the formulas of the products formed from the reaction of 2 -butene with each of the following substances: (a) \(\mathrm{H}_{2} ;\) (b) \(\mathrm{Cl}_{2} ;\) (c) \(\mathrm{HCl} ;\) (d) \(\mathrm{H}_{2} \mathrm{O}\) (in acid).

Short Answer

Expert verified
The products formed from the reaction of 2-butene with the given substances are: (a) butane, (b) 2,3-dichlorobutane, (c) 2-chlorobutane, and (d) 2-butanol.

Step by step solution

01

Hydrogenation of 2-Butene

Reaction (a) is an example of hydrogenation, where molecular hydrogen (\(\mathrm{H}_2\)) is added to the alkene. In this case, hydrogen is added to 2-butene, resulting in butane. This reaction removes the double bond and turns the alkene into an alkane. The general formula for this reaction is \( \mathrm{RCH=CHR} + \mathrm{H}_2 \rightarrow \mathrm{RCH}_2\mathrm{CHR}_2\). Replace \(\mathrm{R}\) with an ethyl group (\(\mathrm{-CH_2CH_3}\)) to get the product for this specific case, which will yield butane (\(\mathrm{C}_4\mathrm{H}_{10}\)).
02

Halogenation of 2-Butene

Reaction (b) is a halogenation reaction, where a halogen is added across the double bond in the alkene. In 2-butene's case, it reacts with \(\mathrm{Cl}_2\) to form 2,3-dichlorobutane. The general formula is \(\mathrm{RCH=CHR} + \mathrm{X}_2 \rightarrow \mathrm{RCHX-CHXR}\). Replace \(\mathrm{R}\) with an ethyl group (\(\mathrm{-CH_2CH_3}\)) and \(\mathrm{X}\) with a Chlorine atom (\(\mathrm{Cl}\)), and this will yield 2,3-dichlorobutane (\(\mathrm{C}_4\mathrm{H}_8\mathrm{Cl}_2\)).
03

Hydrohalogenation of 2-Butene

Reaction (c) is a hydrohalogenation reaction, where a hydrogen halide (in this case \(\mathrm{HCl}\)) is added to the alkene. This results in 2-chlorobutane. For this specific case, follow the general equation \(\mathrm{RCH=CHR} + \mathrm{HX} \rightarrow \mathrm{RCHX-CH_2R}\). Again, replace \(\mathrm{R}\) with an ethyl group (\(\mathrm{-CH_2CH_3}\)) and \(\mathrm{X}\) with a Chlorine atom (\(\mathrm{Cl}\)), and the product is 2-chlorobutane (\(\mathrm{C}_4\mathrm{H}_9\mathrm{Cl}\)).
04

Hydration of 2-Butene

Finally, for reaction (d), 2-butene undergoes hydration in the presence of an acid to form 2-butanol. This is the general reaction \(\mathrm{RCH=CHR} + \mathrm{H}_2\mathrm{O} \rightarrow \mathrm{RCHOH-CH_2R}\). Replacing \(\mathrm{R}\) with an ethyl group (\(\mathrm{-CH_2CH_3}\)) will yield 2-butanol (\(\mathrm{C}_4\mathrm{H}_9\mathrm{OH}\)).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free