All-purpose fertilizers contain the essential elements nitrogen, phosphorus, and potassium. A typical fertilizer carries numbers on its label, such as "5-10-5". These numbers represent the \% \(\mathrm{N}, \% \mathrm{P}_{2} \mathrm{O}_{5},\) and \(\% \mathrm{K}_{2} \mathrm{O},\) respectively. The \(\mathrm{N}\) is contained in the form of a nitrogen compound, such as \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}, \mathrm{NH}_{4} \mathrm{NO}_{3}\) or \(\mathrm{CO}\left(\mathrm{NH}_{2}\right)_{2}\) (urea). The \(\mathrm{P}\) is generally present as a phosphate, and the \(K\) as \(K C\). The expressions \(\% \mathrm{P}_{2} \mathrm{O}_{5}\) and \(\% \mathrm{K}_{2} \mathrm{O}\) were devised in the nineteenth century, before the nature of chemical compounds was fully understood. To convert from \% \(\mathrm{P}_{2} \mathrm{O}_{5}\) to \% \(\mathrm{P}\) and from \% \(\mathrm{K}_{2} \mathrm{O}\) to \% \(\mathrm{K}\), the factors \(2 \mathrm{mol} \mathrm{P} / \mathrm{mol}\) \(\mathrm{P}_{2} \mathrm{O}_{5}\) and \(2 \mathrm{mol} \mathrm{K} / \mathrm{mol} \mathrm{K}_{2} \mathrm{O}\) must be used, together with molar masses. (a) Assuming three-significant-figure precision, what is the percent composition of the "5-10-5" fertilizer in \% \(\mathrm{N}, \% \mathrm{P},\) and \(\% \mathrm{K} ?\) (b) What is the \(\% \mathrm{P}_{2} \mathrm{O}_{5}\) in the following compounds (both common fertilizers)? (i) \(\mathrm{Ca}\left(\mathrm{H}_{2} \mathrm{PO}_{4}\right)_{2}\) (ii) \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4}\) (c) In a similar manner to the "5-10-5" fertilizer described in this exercise, how would you describe a fertilizer in which the mass ratio of \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4}\) to KCl is 5.00:1.00? (d) Can a "5-10-5" fertilizer be prepared in which \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4}\) and \(\mathrm{KCl}\) are the sole fertilizer components, with or without inert nonfertilizer additives? If so, what should be the proportions of the constituents of the fertilizer mixture? If this "5-10-5" fertilizer cannot be prepared, why not?

Short Answer

Expert verified
The percentage composition of 5-10-5 will vary depending on the molar mass and the molar mass of the particular formula used. The percentage compositions of \(P_{2}O_{5}\) in common fertilizers will be calculated accordingly, using their respective formulas and molar masses. The ratios of the content in a new fertilizer can be calculated using the provided mass ratios. And finally, whether or not a '5-10-5' fertilizer can be prepared from given components will depend on the possible combinations of the compounds based on their chemical composition.

Step by step solution

01

Calculation of Percentage Composition of 5-10-5 Fertilizer

The given numbers denote the percentages of \(N\), \(P_{2}O_{5}\), and \(K_{2}O\). We'll need to convert those for \(P_{2}O_{5}\) and \(K_{2}O\) into percentages for \(P\) and \(K\). Since 1 mol \(P_{2}O_{5}\) contains 2 mol \(P\) and 1 mol \(K_{2}O\) contains 2 mol \(K\), you can find equivalence in percentages using the molar masses of \(P_{2}O_{5}\), \(P\), \(K_{2}O\), and \(K\). Find those molar masses(using periodic table), then calculate the percentage composition for \(P\) and \(K\) using the given percentage composition for \(P_{2}O_{5}\) and \(K_{2}O\).
02

Calculation of Percentage Composition of \(P_{2}O_{5}\) in the Given Fertilizers

To find the percentage composition of \(P_{2}O_{5}\) in the given compounds, first calculate the molar mass of each given compound and the molar mass of \(P_{2}O_{5}\) present in each of them. Then, use this to calculate the percentage composition of \(P_{2}O_{5}\) in each fertilizer.
03

Describing a New Fertilizer

Given a mass ratio of \( (NH_{4})_{2}HPO_{4}\) to KCl as 5.00:1.00, use this to describe the new fertilizer in terms of the percenatge compositions of \(N\), \(P\), and \(K\).
04

Preparation of 5-10-5 Fertilizer

To find whether a '5-10-5' fertilizer can be prepared using \( (NH_{4})_{2}HPO_{4}\) and KCl, perform analysis similar to steps above. If it cannot be prepared, explain why not using results of calculations and material balances.

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