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Chapter 3: Problem 120

The compound \(\mathrm{C}_{7} \mathrm{H}_{7} \mathrm{NO}_{2}\) contains (a) 17 atoms per mole; (b) equal percents by mass of \(\mathrm{C}\) and \(\mathrm{H} ;\) (c) about twice the percent by mass of \(\mathrm{O}\) as of \(\mathrm{N} ;\) (d) about twice the percent by mass of \(\mathrm{N}\) as of \(\mathrm{H}\).

Short Answer

Expert verified
Firstly, calculate the molar mass of C7H7NO2. Then, calculate the mass contribution of each element in the compound. Up next, compute the percent by mass of each element. Confirm if the given conditions in the exercise are met. If it's found that the percent by mass of Carbon is approximately equal to Hydrogen's, Oxygen's is about two times Nitrogen's, and Nitrogen's is about twice as much as Hydrogen's, then the exercise has been correctly solved.

Step by step solution

01

Compute the Molar Mass of the Compound

To compute the molar mass of the compound C7H7NO2, add up the atomic masses for each element according to its quantity given by the subscript in the molecular formula. The atomic masses of Carbon (C), Hydrogen (H), Nitrogen (N), and Oxygen (O) are roughly 12.01 g/mol, 1.008 g/mol, 14.007 g/mol, and 16.00 g/mol respectively. Therefore, the molar mass is computed as: Molar Mass = (7*12.01 g/mol) + (7*1.008 g/mol) + (1*14.007 g/mol) + (2*16.00 g/mol).
02

Calculate the Mass of Each Element

Calculate the mass contribution of each element in the compound. For Carbon: Mass = (7*12.01 g/mol). For Hydrogen: Mass = (7*1.008 g/mol). For Nitrogen: Mass = (1*14.007 g/mol). For Oxygen: Mass = (2*16.00 g/mol).
03

Calculate the Percent by Mass of Each Element

Now calculate the percent by mass of each element. The percent by mass is calculated by taking the mass of the element (calculated in Step 2) and dividing it by the molar mass (calculated in Step 1), then multiplying the result by 100. For example, the percent by mass for Carbon = [(mass of carbon) / (molar mass of C7H7NO2)] * 100
04

Confirm the Given Conditions

Confirm that the percent by mass of Carbon is almost equal to that of Hydrogen, the percent by mass of Oxygen is about twice that of Nitrogen, and the percent by mass of Nitrogen is about twice that of Hydrogen. If these conditions are met, then the exercise has been solved correctly.

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