An isomer of the compound \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHOHCH}_{3}\) is (a) \(\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O} ;\) (b) \(\mathrm{CH}_{3} \mathrm{CHOHCH}_{2} \mathrm{CH}_{3}\) (c) \(\mathrm{CH}_{3}\left(\mathrm{CH}_{2}\right)_{2} \mathrm{OH} ;\) (d) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OCH}_{2} \mathrm{CH}_{3}\)

Short Answer

Expert verified
The isomer of the compound \(\mathrm{CH}_{3} \mathrm{CH}_{2}\mathrm{CHOHCH}_{3}\) is \(\mathrm{CH}_{3}\mathrm{CHOHCH}_{2} \mathrm{CH}_{3}\).

Step by step solution

01

Identify the Original Compound

First, we identify the initial compound, which is \(\mathrm{CH}_{3} \mathrm{CH}_{2}\mathrm{CHOHCH}_{3}\). It contains four carbon atoms (C), nine Hydrogen atoms (H) and one Oxygen atom (O). Thus, its molecular formula is \(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{O}\).
02

Compare with Options

Next, we compare this with the given choices. The molecular formulae for the options provided are - (a) \(\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}\), (b) \(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{O}\), (c) \(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{O}\), and (d) \(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{O}\). An isomer would share the same molecular formula, but the arrangement of the atoms would be different.
03

Identify the Isomer

Given that isomers share the same molecular formula, we can rule out option (a) because it does not match the formula \(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{O}\). Comparing the structural diagrams of the original compound and the other options, we find that option (b) \(\mathrm{CH}_{3}\mathrm{CHOHCH}_{2} \mathrm{CH}_{3}\) differs in the placement of the OH group, thus it is the isomer of the original compound.

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