The hemoglobin content of blood is about \(15.5 \mathrm{g} / 100 \mathrm{mL}\) blood. The molar mass of hemoglobin is about \(64,500 \mathrm{g} / \mathrm{mol},\) and there are four iron (Fe) atoms in a hemoglobin molecule. Approximately how many Fe atoms are present in the 6 Lof blood in a typical adult?

Short Answer

Expert verified
The number of Fe atoms present in the blood of a typical adult is approximately \(3.381 \times 10^{25}\)

Step by step solution

01

Convert the quantity of blood to mL

An adult has 6 L of blood, which converts to \(6000 \mathrm{mL}\) since \(1 \mathrm{L} = 1000 \mathrm{mL}\).
02

Find the mass of hemoglobin in this volume

If there is \(15.5 \mathrm{g}\) of hemoglobin in \(100 \mathrm{mL}\) of blood, then in \(6000 \mathrm{mL}\) of blood there will be \( \xi = \frac{6000 \times 15.5}{100} = 930 \mathrm{g} \) of hemoglobin, where \(\xi\) refers to the required quantity of hemoglobin.
03

Convert the mass of hemoglobin to moles

Knowing that the molar mass of hemoglobin is \(64500 \mathrm{g/mol}\), the molar quantity \(\eta\) of hemoglobin is found using the formula: \(\eta = \frac{\xi}{64500} = 0.014 \mathrm{mol}\)
04

Calculate the number of Fe atoms

Each molecule of hemoglobin contains 4 atoms of Fe. Therefore, the number of iron atoms is \(4 \times \eta \times 6.022 \times 10^{23} = 3.381 \times 10^{25}\)

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