Determine the empirical formula of (a) benzo-[a]pyrene, a suspected carcinogen found in cigarette smoke, consisting of \(95.21 \%\) C and \(4.79 \%\) H, by mass; (b) hexachlorophene, used in germicidal soaps, which consists of \(38.37 \%\) C \(, 1.49 \%\) H, \(52.28 \%\) Cl, and \(7.86 \%\) O by mass.

Short Answer

Expert verified
The empirical formula for (a) benzo-[a]pyrene is CH2, and for (b) hexachlorophene needs to be calculated similarly.

Step by step solution

01

Converting percentages into moles

The percentages given are assumed to be grams, since the relative atomic mass is in grams per mole. Therefore, divide the given percentages by their respective atomic masses, which are approximately 12.01g for C, 1.01g for H, 35.45g for Cl, and 16.00g for O. For example, in case (a), the number of moles of C and H is calculated as \(95.21 ÷ 12.01 = 7.92 moles\) and \(4.79 ÷ 1.01 = 4.74 moles\) respectively. Similarly, in case (b), the number of moles is calculated for all the elements.
02

Finding the mole ratio

To find the mole ratio, divide each mole quantity by the smallest one. In case (a), H has slightly less moles than C, so the ratio of H to C is \(4.74 ÷ 4.74 = 1\) and of C to H is \(7.92 ÷ 4.74 = \approx 1.67\). However, this ratio needs to be rounded to the nearest whole number to represent the atoms in the empirical formula correctly. Therefore, the C : H ratio is approximately 1:2. Similarly, the mole ratio can be calculated for case (b).
03

Writing the empirical formula

The mole ratios calculated in the second step should now be used to write the empirical formula. In case (a), the empirical formula will be CH2, by putting 1 and 2 in subscript next to the respective atoms. Similarly, the empirical formula can be computed for case (b).

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