The organic solvent thiophene is a carbon-hydrogensulfur compound that yields \(\mathrm{CO}_{2}, \mathrm{H}_{2} \mathrm{O},\) and \(\mathrm{SO}_{2}\) when burned in an excess of oxygen. When subjected to combustion analysis, a \(1.3020 \mathrm{g}\) sample of thiophene produces \(2.7224 \mathrm{g} \mathrm{CO}_{2}, 0.5575 \mathrm{g} \mathrm{H}_{2} \mathrm{O},\) and \(0.9915 \mathrm{g} \mathrm{SO}_{2} .\) What is the empirical formula of thiophene?

Short Answer

Expert verified
The empirical formula of thiophene is \(\mathrm{C}_4\mathrm{H}_4\mathrm{S}\).

Step by step solution

01

Determine the Masses of C, H and S

From the combustion, 2.7224g of \(\mathrm{CO}_2\) gives the mass of C as: \((12.01 / 44.01) \times 2.7224 \mathrm{g}\) \(\mathrm{CO}_2\). H from 0.5575g \(\mathrm{H}_2\mathrm{O}\) is: \((2.016 / 18.015) \times 0.5575 \mathrm{g}\) \(\mathrm{H}_2\mathrm{O}\). And S from 0.9915g \(\mathrm{SO}_2\) is: \((32.065 / 64.066) \times 0.9915 \mathrm{g}\) \(\mathrm{SO}_2\).
02

Calculate the Number of Moles

The number of moles is given by the mass divided by the molar mass. Calculate the number of moles for C, H, and S using their respective molar masses of 12.01 g/mol, 1.008 g/mol, and 32.065 g/mol.
03

Determine the Empirical Formula

To determine the empirical formula, divide each of the number of moles calculated by the smallest number obtained. Then, round to the nearest whole number to get the ratio and therefore the formula.

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