Nitrogen forms five oxides in which its oxidation states are \(+1,+2,+3,+4,\) and \(+5,\) respectively. Write appropriate formulas for these compounds.

Short Answer

Expert verified
The formulas for the oxides of Nitrogen for the indicated oxidation states are \(NO\), \(N_2O\), \(NO_2\), \(N_2O_3\), and \(N_2O_5\), respectively.

Step by step solution

01

Oxidation state +1

The oxidation state of Nitrogen is +1 and Oxygen is -2. The compound that satisfies these oxidation states is \(NO\), where Nitrogen is in +1/2 oxidation state for each Oxygen atom.
02

Oxidation state +2

The oxidation state of Nitrogen is +2 and Oxygen is -2. The compound that satisfies these oxidation states is \(N_2O\), where Nitrogen is in +1 oxidation state for each Oxygen atom.
03

Oxidation state +3

The oxidation state of Nitrogen is +3 and Oxygen is -2. The compound that satisfies these oxidation states is \(NO_2\), where Nitrogen is in +4 oxidation state for each Oxygen atom.
04

Oxidation state +4

The oxidation state of Nitrogen is +4 and Oxygen is -2. The compound that satisfies these oxidation states is \(N_2O_3\), where Nitrogen is in +3/2 oxidation state for each Oxygen atom.
05

Oxidation state +5

The oxidation state of Nitrogen is +5 and Oxygen is -2. The compound that satisfies these oxidation states is \(N_2O_5\), where Nitrogen is in +5/2 oxidation state for each Oxygen atom.

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