Without per forming detailed calculations, determine the hydrate of \(\mathrm{Na}_{2} \mathrm{SO}_{3}\) that contains almost exactly \(50 \%\) \(\mathrm{H}_{2} \mathrm{O},\) by mass.

Short Answer

Expert verified
The hydrate of \( \mathrm{Na}_{2} \mathrm{SO}_{3} \) that contains almost exactly 50% \( \mathrm{H}_{2} \mathrm{O} \), by mass is \( \mathrm{Na}_{2} \mathrm{SO}_{3} \cdot 7 \mathrm{H}_{2} \mathrm{O} \).

Step by step solution

01

Determine the molar mass of Na2SO3 and H2O

First, we need to calculate the molar mass of Na2SO3 and H2O. We use the periodic table to find the molar masses of the individual elements. The molar mass of Na2SO3 is approximately 126 g/mol (23*2 for two Na atoms, 32 for S, and 16*3 for three O atoms) and the molar mass of H2O is approximately 18 g/mol (1*2 for two H atoms and 16 for O). Notice that we are ignoring some decimal points; this approximation is acceptable assuming the exercise instruction.
02

Apply the ratio analysis for the 50% H2O mass

If the hydrate contains exactly 50% H2O by mass, then for every 'x' grams of Na2SO3, we have 'x' grams of H2O too. Therefore, for every 1 mol (126 grams) of Na2SO3, we have \( \frac{x}{18} \) mols of H2O, where 'x' is the mass of H2O in grams. As 'x' is supposed to be equal to 126 grams, the number of mols of H2O is \( \frac{126}{18} = 7 \).
03

Identify the hydrate

The number of water molecules per molecule of Na2SO3 in the hydrate is given by the number of moles of water. In this case, it is 7. Therefore, the formula of the hydrate is \( \mathrm{Na}_{2} \mathrm{SO}_{3} \cdot 7 \mathrm{H}_{2} \mathrm{O} \).

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