Write the condensed structural formulas for the organic compounds: (a) octane (b) heptanoic acid (c) 3-hexanol (d) 2 -chlorobutane

Short Answer

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The condensed structural formulas are: (a) Octane: \(C_8H_{18}\), (b) Heptanoic Acid: \(C_7H_{14}O_2\), (c) 3-Hexanol: \(C_6H_{13}OH\), (d) 2 -Chlorobutane: \(C_4H_9Cl\)

Step by step solution

01

Octane

The prefix 'oct' refers to eight carbon atoms, and the 'ane' indicates that it's an alkane. Therefore, the condensed structural formula will be \(C_8H_{18}\)
02

Heptanoic Acid

The prefix 'hept' implies a chain of seven carbon atoms, and 'anoic acid' indicates that it's a carboxylic acid. Therefore, the condensed structural formula will be \(C_7H_{14}O_2\)
03

3-Hexanol

The prefix 'hex' signifies six carbon atoms, and the 'ol' suffix denotes an alcohol. The '3' in the front refers to the position of the hydroxy group (-OH) on the third carbon atom. Therefore, the condensed structural formula will be \(C_6H_{13}OH\)
04

2-Chlorobutane

The prefix 'but' denotes four carbon atoms, 'ane' signifies that it's an alkane, and '2-Chloro' indicates there is a Chlorine atom attached on the second carbon. Therefore, the condensed structural formula will be \(C_4H_9Cl\)

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