All the silver in a \(26.39 \mathrm{g}\) sample of impure silver is converted to silver chloride. If 31.56 g of silver chloride are obtained, then what is the mass percent of silver in the sample?

Short Answer

Expert verified
The mass percent of silver in the sample is \(89.93%\)

Step by step solution

01

- 'Calculate the Molar Masses'

Calculate the molar masses of silver (Ag) and chlorine (Cl). From the periodic table, the molar mass of Ag is \(107.87 \mathrm{g/mol}\) and that of Cl is \( 35.45 \mathrm{g/mol}\). This makes the molar mass of silver chloride (AgCl) be the sum of the molar masses of Ag and Cl, which equals \(143.32 \mathrm{g/mol}\).
02

- 'Determine the weight of silver in silver Chloride'

Calculate the mass of silver in the 31.56 g of silver chloride obtained. Given that the mass of a sample of a substance is the product of its molar mass and number of moles, rearrange this equation to find the number of moles as \(moles = mass/molar mass\). Substituting for the mass of silver chloride and its molar mass, the number of moles of AgCl is \(0.220 moles\). Since silver chloride consists of one mole of silver for every mole of chloride, the moles of silver is also \(0.220 moles\), which makes its mass be the product of its number of moles and its molar mass. That is, \(mass_{Ag} = moles_{Ag} * molar mass_{Ag} = 0.220 moles * 107.87 g/mol = 23.73 g\).
03

- 'Calculate the Mass percent'

Calculate the mass percent of silver in the sample. Use the formula for calculating mass percent, which is \(mass percent = (mass of the constituent/ mass of the compound)*100 %\). Substituting the figures into the formula, the mass percent of silver in the sample is \((23.73 g / 26.39 g) * 100% = 89.93%\).

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Most popular questions from this chapter

A formula unit of the compound \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{SO}_{4}\) has nearly equal masses of (a) \(\mathrm{S}\) and \(\mathrm{O} ;\) (b) \(\mathrm{N}\) and \(\mathrm{O}\) (c) \(\mathrm{H}\) and \(\mathrm{N} ;\) (d) \(\mathrm{Cu}\) and \(\mathrm{O}\)

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