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Chapter 4: Problem 103

What is the molarity of \(\mathrm{NaCl}(\mathrm{aq})\) if a solution has 1.52 ppm Na? Assume that NaCl is the only source of Na and that the solution density is \(1.00 \mathrm{g} / \mathrm{mL}\) (The unit \(p p m\) is parts per million; here it can be taken to mean g Na per million grams of solution.)

Short Answer

Expert verified
The molarity of the NaCl solution is \(6.61*10^{-5} M\).

Step by step solution

01

Convert ppm into g Na

To start, ppm is parts per million, which can be understood as grams of Na per million grams of solution. Therefore, 1.52 ppm Na means there are 1.52 grams of Na in 1 million grams of the solution. (As one million grams is 1000 kg or 1000 L, considering the density of the solution = 1 g/mL).
02

Convert g Na into Na moles

Since Na is the only source of Na+, the amount of Na is equal to the amount of NaCl in the solution. The molar mass of Na is approximately 23 g/mol. To convert the amount of Na from grams into moles, divide it by the molar mass of Na. This gives, \( \frac{1.52 \, \text{g}}{23 \, \text{g/mol}} = 0.0661 \, \text{moles}\).
03

Calculate Molarity

Molarity (M) is defined as the number of moles of solute per liter of solution. Given that the solution volume is 1000 L (since 1 million grams is equal 1 million mL or 1000 L, the density of the solution = 1 g/mL), the molarity is, \( M = \frac{0.0661 \, \text{moles}}{1000 \, \text{L}} = 6.61*10^{-5} M \).

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Most popular questions from this chapter

Appendix E describes a useful study aid known as concept mapping. Using the method presented in Appendix \(\mathrm{E},\) construct a concept map relating the topics found in Sections \(4-3,4-4,\) and \(4-5\).

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