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Chapter 4: Problem 122

For a specific reaction, ammonium dichromate is the only reactant and chromium(III) oxide and water are two of the three products. What is the third product and how many grams of this product are produced per kilogram of ammonium dichromate decomposed?

Short Answer

Expert verified
The third product is Nitrogen gas (\( N_2 \)). Approximately 111.17 g of this product are produced per kilogram of ammonium dichromate decomposed.

Step by step solution

01

Identify the Balanced Chemical Reaction

Firstly, the balanced chemical reaction for the decomposition of ammonium dichromate (\( (NH_4)_2Cr_2O_7 \)) is: \[ (NH_4)_2Cr_2O_7 \rightarrow Cr_2O_3 + 4 H_2O + N_2 \] So, the third product is Nitrogen gas (\( N_2 \))
02

Calculate Molar Masses

Next, calculate the molar masses of the reactant and the third product: \[ Molar\ mass\ of\ (NH_4)_2Cr_2O_7 = 252.07\ g/mol \] \[ Molar\ mass\ of\ N_2 = 28.014\ g/mol \]
03

Calculate the Amount of Third Product Produced

The stoichiometry of the reaction tells us that 1 mole of \( (NH_4)_2Cr_2O_7 \) decomposed yields 1 mole of \( N_2 \). So, if we have 1000 g (1 kg) of \( (NH_4)_2Cr_2O_7 \), this corresponds to \( \frac{1000}{252.07} \) moles. Hence, the same number of moles of \( N_2 \) is produced, which corresponds to \( \frac{1000}{252.07} \times 28.014 = 111.17 \) g of \( N_2 \).

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Most popular questions from this chapter

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