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Chapter 4: Problem 143

The incomplete combustion of gasoline produces \(\mathrm{CO}(\mathrm{g})\) as well as \(\mathrm{CO}_{2}(\mathrm{g}) .\) Write an equation for \((\mathrm{a})\) the complete combustion of the gasoline component octane, \(\mathrm{C}_{8} \mathrm{H}_{18}(\mathrm{l}),\) and \((\mathrm{b})\) incomplete combustion of octane with \(25 \%\) of the carbon appearing as \(\mathrm{CO}(\mathrm{g})\)

Short Answer

Expert verified
The reaction equations for the complete and incomplete combustion of octane are:Complete combustion: \(C_8H_{18}(l) + 12.5O_2(g) \rightarrow 8CO_{2}(g) + 9H_{2}O(l)\)Incomplete combustion (25% CO): \(C_8H_{18}(l) + 9.5O_2(g) \rightarrow 6CO_{2}(g) + 2CO(g) + 9H_{2}O(l)\)

Step by step solution

01

Complete Combustion of Octane

Complete combustion of a hydrocarbon involves reaction with oxygen to produce only carbon dioxide (CO2) and water (H2O). So, this combustion can be represented as: \(C_8H_{18}(l) + 12.5O_2(g) \rightarrow 8CO_{2}(g) + 9H_{2}O(l)\)In this reaction, octane (C8H18) is combusted completely, resulting in 8 molecules of CO2 and 9 molecules of H2O.
02

Determine Carbon in CO for Incomplete Combustion

For incomplete combustion, where 25% of carbon is converted into CO, first calculate how many carbon atoms will be appearing as CO: 25% of 8 Carbon atoms in Octane = 0.25 * 8 = 2 Hence, 2 out of 8 carbon atoms will appear as CO.
03

Incomplete Combustion of Octane

Now that we know 2 carbon atoms end up as CO, the rest 6 Carbon atoms will go to CO2. So, for incomplete combustion, the reaction would look like this:\(C_8H_{18}(l) + 9.5O_2(g) \rightarrow 6CO_{2}(g) + 2CO(g) + 9H_{2}O(l)\)Here, the octane (C8H18) is not combusted completely, leading to production of 2 molecules of CO, 9 molecules of H2O and 6 molecules of CO2.

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Most popular questions from this chapter

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