High-purity silicon is obtained using a three-step process. The first step involves heating solid silicon dioxide, \(\mathrm{SiO}_{2^{\prime}}\) with solid carbon to give solid silicon and carbon monoxide gas. In the second step, solid silicon is converted into liquid silicon tetrachloride, \(\mathrm{SiCl}_{4}\) by treating it with chlorine gas. In the last step, \(\mathrm{SiCl}_{4}\) is treated with hydrogen gas to give ultrapure solid silicon and hydrogen chloride gas. (a) Write balanced chemical equations for the steps involved in this three- step process. (b) Calculate the masses of carbon, chlorine, and hydrogen required per kilogram of silicon.

Short Answer

Expert verified
Balanced chemical equations: 1) \( \mathrm{SiO}_{2} + 2C \rightarrow Si + 2CO \), 2) \( Si + 2Cl_{2} \rightarrow SiCl_{4} \), 3) \( SiCl_{4} + 2H_{2} \rightarrow Si + 4HCl \). Masses required per kg of silicon: Carbon = \( \frac{1000}{28} \times 2 \times 12 \) grams, Chlorine = \( \frac{1000}{28} \times 2 \times 71 \) grams, Hydrogen = \( \frac{1000}{28} \times 2 \times 2 \) grams.

Step by step solution

01

Balance the chemical equations

Write the chemical reactions for each step and balance them. For step one, the reaction is: \[ \mathrm{SiO}_{2} + 2C \rightarrow Si + 2CO \] For step two, the reaction is: \[ Si + 2Cl_{2} \rightarrow SiCl_{4} \] And for step three, we have: \[ SiCl_{4} + 2H_{2} \rightarrow Si + 4HCl \]
02

Stoichiometry calculations for carbon

For each kg (or 1000 grams) of silicon, how many grams of carbon are needed? Looking at the first balanced equation, you can see that one mole of Si requires 2 moles of C to produce. The molar mass of Si is approximately 28 grams/mole and for C, it's about 12 grams/mole. Therefore, \[ \frac{1000}{28} \] moles of Si require \[ \frac{1000}{28} \times 2 \] moles of C, which equates to \[ \frac{1000}{28} \times 2 \times 12 \] grams of C.
03

Stoichiometry calculations for chlorine and hydrogen

Next, determine the mass of chlorine and hydrogen required per kg of silicon. From the second and third balanced equations, it can be seen that one mole of Si requires 2 moles of \( Cl_{2} \) and 2 moles of \( H_{2} \) respectively. The molar mass of \( Cl_{2} \) is approximately 71 grams/mole and for \( H_{2} \), it's about 2 grams/mole. Therefore, \[ \frac{1000}{28} \] moles of Si require \[ \frac{1000}{28} \times 2 \] moles of \( Cl_{2} \) and \( H_{2} \), which equates to \[ \frac{1000}{28} \times 2 \times 71 \] grams of \( Cl_{2} \) and \[ \frac{1000}{28} \times 2 \times 2 \] grams of \( H_{2} \) respectively.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Ammonia can be generated by heating together the solids \(\mathrm{NH}_{4} \mathrm{Cl}\) and \(\mathrm{Ca}(\mathrm{OH})_{2} . \mathrm{CaCl}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\) are also formed. (a) If a mixture containing \(33.0 \mathrm{g}\) each of \(\mathrm{NH}_{4} \mathrm{Cl}\) and \(\mathrm{Ca}(\mathrm{OH})_{2}\) is heated, how many grams of \(\mathrm{NH}_{3}\) will form? (b) Which reactant remains in excess, and in what mass?

A 99.8 mL sample of a solution that is \(120 \%\) KI by mass \((d=1.093 \mathrm{g} / \mathrm{mL})\) is added to \(96.7 \mathrm{mL}\) of another solution that is \(14.0 \% \mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}\) by mass \((d=1.134 \mathrm{g} / \mathrm{mL})\) How many grams of \(\mathrm{PbI}_{2}\) should form? \(\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{aq})+2 \mathrm{KI}(\mathrm{aq}) \longrightarrow \mathrm{PbI}_{2}(\mathrm{s})+2 \mathrm{KNO}_{3}(\mathrm{aq})\)

Iron ore is impure \(\mathrm{Fe}_{2} \mathrm{O}_{3} .\) When \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) is heated with an excess of carbon (coke), metallic iron and carbon monoxide gas are produced. From a sample of ore weighing \(938 \mathrm{kg}, 523 \mathrm{kg}\) of pure iron is obtained. What is the mass percent \(\mathrm{Fe}_{2} \mathrm{O}_{3},\) by mass, in the ore sample, assuming that none of the impurities contain Fe?

A drop \((0.05 \mathrm{mL})\) of \(12.0 \mathrm{M} \mathrm{HCl}\) is spread over a sheet of thin aluminum foil. Assume that all the acid reacts with, and thus dissolves through, the foil. What will be the area, in \(\mathrm{cm}^{2}\), of the cylindrical hole produced? (Density of \(\mathrm{Al}=2.70 \mathrm{g} / \mathrm{cm}^{3} ;\) foil thickness \(=0.10 \mathrm{mm} .)\) \(2 \mathrm{Al}(\mathrm{s})+6 \mathrm{HCl}(\mathrm{aq}) \longrightarrow 2 \mathrm{AlCl}_{3}(\mathrm{aq})+3 \mathrm{H}_{2}(\mathrm{g})\)

It is desired to produce as large a volume of \(1.25 \mathrm{M}\) urea \(\left[\mathrm{CO}\left(\mathrm{NH}_{2}\right)_{2}(\mathrm{aq})\right]\) as possible from these three sources: \(345 \mathrm{mL}\) of \(1.29 \mathrm{M} \mathrm{CO}\left(\mathrm{NH}_{2}\right)_{2}, 485 \mathrm{mL}\) of \(0.653 \mathrm{M}\) \(\mathrm{CO}\left(\mathrm{NH}_{2}\right)_{2},\) and \(835 \mathrm{mL}\) of \(0.775 \mathrm{M} \mathrm{CO}\left(\mathrm{NH}_{2}\right)_{2} .\) How can this be done? What is the maximum volume of this solution obtainable?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free