What volume of \(0.0962 \mathrm{M} \mathrm{NaOH}\) is required to exactly neutralize \(10.00 \mathrm{mL}\) of \(0.128 \mathrm{M} \mathrm{HCl} ?\)

Short Answer

Expert verified
The required volume of \(0.0962 \, \mathrm{M} \, \mathrm{NaOH}\) needed to neutralize \(10.00 \, \mathrm{ml}\) of \(0.128 \, \mathrm{M} \, \mathrm{HCl}\) is \(13.3 \, \mathrm{ml}\).

Step by step solution

01

Determine the Amount of Moles of HCl

Calculate the moles of HCl using its volume and molarity. The molarity (\(M\)) could be defined as moles of solute per litre of solution (\(M=n/V\)). Therefore, to calculate the number of moles (\(n\)), we multiply the volume (\(V = 10.00 \, \mathrm{ml}\)) by its molarity (\(M = 0.128 \, \mathrm{M}\)). We convert the volume from ml to L (since molarity is in terms of L) by dividing by 1000. Then we solve, \(n=(10.00/1000) \times 0.128 = 0.00128 \, \mathrm{moles}\) of HCl.
02

Use Stoichiometry of the Balanced Equation

According to the balanced equation for the reaction, one mole of HCl reacts with one mole of NaOH. Consequently, the number of moles of NaOH required for neutralization equals the number of moles of HCl, which is \(0.00128 \, \mathrm{moles}\).
03

Compute the Volume of NaOH Needed

Now the calculated moles of NaOH can be used to find the volume needed by using rearranged molarity formula: \(V=n/M\). Here, \(n=0.00128 \, \mathrm{moles}\) and \(M=0.0962 \, \mathrm{M}\). After calculating, we find that \(V=0.00128/0.0962 = 0.0133 \, \mathrm{L} = 13.3 \, \mathrm{ml}\).

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