A 72.8 L constant-volume cylinder containing \(7.41 \mathrm{g}\) He is heated until the pressure reaches 3.50 atm. What is the final temperature in degrees Celsius?

Short Answer

Expert verified
The final temperature of the gas is \(\approx 1977.17\) degrees Celsius.

Step by step solution

01

Convert mass of Helium to moles

To apply the Ideal Gas Law, the number of moles of the gas is needed. Helium (He) has a molar mass of \(4.0026 \mathrm{g / mol}\) approximately, so use the given mass \(7.41 \mathrm{g}\) to calculate the number of moles \(n\) using the formula: \(n = \frac{mass}{molar~mass}\) .
02

Convert pressure to the standard unit

Convert the given pressure from atmospheres to Pascal which is the standard unit of pressure for the Ideal Gas Law. The conversion factor is \(1 \text{ atm} = 1.01325 \times 10^5 \text{ Pa}\). So multiply the given pressure by the conversion factor.
03

Apply the Ideal Gas Law

Substitute the values of pressure \(P\), volume \(V\), moles \(n\) and the gas constant \(R = 8.314 \text{ J/mol K}\) into the Ideal Gas law and solve for the final temperature \(T\). Remember the temperature will be in Kelvin.
04

Convert final temperature to Celsius

Convert the final temperature in Kelvin to degrees Celsius using the formula: \(T_{\text{Celsius}} = T_{\text{Kelvin}} - 273.15\)

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Most popular questions from this chapter

In order for a gas-filled balloon to rise in air, the density of the gas in the balloon must be less than that of air. (a) Consider air to have a molar mass of \(28.96 \mathrm{g} / \mathrm{mol}\) determine the density of air at \(25^{\circ} \mathrm{C}\) and \(1 \mathrm{atm},\) in g/L. (b) Show by calculation that a balloon filled with carbon dioxide at \(25^{\circ} \mathrm{C}\) and 1 atm could not be expected to rise in air at \(25^{\circ} \mathrm{C}\)

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