What is the molar mass of a gas found to have a density of \(0.841 \mathrm{g} / \mathrm{L}\) at \(415 \mathrm{K}\) and 725 Torr?

Short Answer

Expert verified
The molar mass of the gas is 29 g/mol.

Step by step solution

01

Convert the units

First, the pressure needs to be converted from Torr to atmospheres, because R's value is usually given in (L.atm)/(mol.K). The conversion factor is 1 atm = 760 Torr. Therefore, the pressure \( P = 725 \, Torr \times (1 \, atm / 760 \, Torr) = 0.953 \, atm\). Also, density d needs to be converted from g/L to mol/L. The conversion factor is 1 g/mol = 1 mol/g. Therefore, the density \( d = 0.841 \, g/L \times (1 \, mol/g) = 0.841 \, mol/L\).
02

Rearrange the formula to solve for M

We need to rearrange the equation derived from the ideal gas law for density to solve for molar mass M. The equation becomes \( M = dRT / P \).
03

Substitute the values

Plug in the values of d, R, T, and P into the rearranged equation. Using R = 0.0821 L.atm/(mol.K), \( M = 0.841 \, mol/L \times 0.0821 \, L.atm/(mol.K) \times 415 \, K / 0.953 \, atm \).
04

Perform the Calculation

After substituting the values into the equation, the calculation \( M = 29 \, g/mol \) is obtained.

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Most popular questions from this chapter

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