What is the pressure (in \(\mathrm{mmHg}\) ) of the gas inside the apparatus below if \(P_{\text {bar. }}=740 \mathrm{mm} \mathrm{Hg}, h_{1}=30 \mathrm{mm}\) and \(h_{2}=50 \mathrm{mm} ?\)

Short Answer

Expert verified
The pressure of the gas inside the apparatus is \(760 \mathrm{mmHg}\).

Step by step solution

01

Identify given values

In this problem, we have: Atmospheric pressure \(P_{\text {bar. }}=740 \mathrm{mm} \mathrm{Hg}\), Height \(h_{1}=30 \mathrm{mm}\), and Height \(h_{2}=50 \mathrm{mm}\).
02

Apply the Barometric Formula

Barometric Pressure Formula is written as \(P_{\text{gas}} = P_{\text {bar. }} - (h_{1} - h_{2})\). Here, \(P_{\text {bar. }}\) is the atmospheric pressure, \(h_{1}\) is the height of mercury level on one side of the manometer, and \(h_{2}\) is the height of the mercury level on one the other side of the manometer.
03

Substitute given values into the formula

Substitute the given values into the formula to get: \(P_{\text{gas}} = 740 \mathrm{mm} \mathrm{Hg} - (30 \mathrm{mm} - 50 \mathrm{mm})\).
04

Calculate

Calculate the equation to get the gas pressure: \(P_{\text{gas}} = 740 \mathrm{mm} \mathrm{Hg} - (-20 \mathrm{mm} \mathrm{Hg})\). Thus, \(P_{\text{gas}} = 760 \mathrm{mm} \mathrm{Hg}\).

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