Calculate the average kinetic energy, \(\bar{e}_{k},\) for \(\mathrm{O}_{2}(\mathrm{g})\) at \(298 \mathrm{K}\) and \(1.00 \mathrm{atm}\)

Short Answer

Expert verified
The average kinetic energy per oxygen molecule, \( \bar{e}_k \), at 298K and 1.00atm is approximately \(6.2 \times 10^{-21} \; \text{J}\).

Step by step solution

01

Identify the Given Variables.

The given temperature (T) is 298K. The Boltzmann constant (k) is a known constant that equals \(1.38 \times 10^{-23} \; \text{J/K}\).
02

Insert the Given Values into the Formula.

Put the values of \(k\) and \(T\) into the formula \( \bar{e}_k = \frac{3}{2} \times k \times T \).
03

Calculate the Average Kinetic Energy.

Now perform the multiplication to calculate the average kinetic energy \( \bar{e}_k = \frac{3}{2} \times (1.38 \times 10^{-23} \; \text{J/K}) \times 298\; \text{K}\).
04

Simplify the Expression.

The result will be the numerical value for \( \bar{e}_k \), which is the average kinetic energy per molecule.

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