Can a chemical compound have a standard enthalpy of formation of zero? If so, how likely is this to occur? Explain.

Short Answer

Expert verified
No, a chemical compound itself would not have a standard enthalpy of formation of zero, but an element in its standard state would. This occurrence is universally true.

Step by step solution

01

Understanding Standard Enthalpy of Formation

In thermodynamics, the standard enthalpy change of formation of a compound is the change of enthalpy during the formation of 1 mole of the substance from its constituent elements, with all substances in their standard states. Note that the standard state of a substance is its phase at 1 atm and 25°C.
02

Case of Zero Enthalpy of Formation

The standard enthalpy of formation for an element in its standard state is zero by definition. This is because there is no change in the substance, as it is already in its elemental form and standard state. So, a compound would not have a standard enthalpy of formation of zero, but an element would since no formation reaction is needed.
03

Likelihood of This Occurrence

All elements in their standard states would have a standard enthalpy of formation of zero. Therefore, this occurrence is not just likely but is universally true, as it is the definition used in thermodynamics.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Thermodynamics
Thermodynamics is the branch of physics that deals with the relationships between heat and other forms of energy. In the realm of chemistry, it provides crucial insight into how energy is exchanged and conserved during chemical reactions. The standard enthalpy of formation is a fundamental concept within thermodynamics, as it quantifies the energy change that occurs when a compound is formed from its elements in their most stable form.

In layman's terms, think of the standard enthalpy of formation like the amount of effort required to create a building from bricks. If the bricks represent the elements, the complete building is the compound. The 'effort' or energy change involved in assembling these basic units into a more complex structure is what we measure with the standard enthalpy of formation. This concept is not only important for understanding energy changes in reactions, but also for determining reaction spontaneity and equilibrium.
Basics of Chemical Compounds
Chemical compounds are substances composed of two or more different types of atoms bonded together. The manner in which atoms combine, the types of atoms involved, and the resulting structures determine the properties and behaviors of the compound. During the formation of a compound from its elemental constituents, bonds are formed, and energy is required or released.

To further elaborate, let's visualize elements as individual letters and compounds as words formed from these letters. Just as arranging letters in a specific way gives meaning to a word, arranging atoms in a certain structure gives unique properties to a compound. The standard enthalpy of formation tells us about the 'cost' or 'gain' of energy when we go from individual letters (elements) to a meaningful word (compound). It's pivotal in chemistry because it helps predict how chemicals will interact with each other.
Significance of Standard States
Standard states are essential reference points in chemistry that provide a basis for comparing thermodynamic quantities, like the standard enthalpy of formation, across different substances. They are the physical states of substances under standard conditions of 1 atm pressure and a specified temperature, commonly 25°C (298 K).

Imagine you're comparing the heights of different people. To be fair, you measure everyone without shoes and on level ground. Similarly, standard states are the 'level ground' for substances in chemistry. By using these uniform conditions, scientists ensure that the values for enthalpy of formation are comparable, avoiding the influence of external factors. This is why, for elements in their most stable form under these conditions, the standard enthalpy of formation is zero — no energy is needed to form an element from itself.

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Most popular questions from this chapter

A clay pot containing water at \(25^{\circ} \mathrm{C}\) is placed in the shade on a day in which the temperature is \(30^{\circ} \mathrm{C} .\) The outside of the clay pot is kept moist. Will the temperature of the water inside the clay pot (a) increase; (b) decrease; (c) remain the same?

Construct a concept map to show the interrelationships between path-dependent and pathindependent quantities in thermodynamics.

We can determine the purity of solid materials by using calorimetry. A gold ring (for pure gold, specific heat \(=0.1291 \mathrm{Jg}^{-1} \mathrm{K}^{-1}\) ) with mass of \(10.5 \mathrm{g}\) is heated to \(78.3^{\circ} \mathrm{C}\) and immersed in \(50.0 \mathrm{g}\) of \(23.7^{\circ} \mathrm{C}\) water in a constant-pressure calorimeter. The final temperature of the water is \(31.0^{\circ} \mathrm{C}\). Is this a pure sample of gold?

Explain the important distinctions between each pair of terms: (a) system and surroundings; (b) heat and work; (c) specific heat and heat capacity; (d) endothermic and exothermic; (e) constant-volume process and constant-pressure process.

An alternative approach to bomb calorimetry is to establish the heat capacity of the calorimeter, exclusive of the water it contains. The heat absorbed by the water and by the rest of the calorimeter must be calculated separately and then added together. A bomb calorimeter assembly containing \(983.5 \mathrm{g}\) water is calibrated by the combustion of \(1.354 \mathrm{g}\) anthracene. The temperature of the calorimeter rises from 24.87 to \(35.63^{\circ} \mathrm{C} .\) When \(1.053 \mathrm{g}\) citric acid is burned in the same assembly, but with 968.6 g water, the temperature increases from 25.01 to \(27.19^{\circ} \mathrm{C}\). The heat of combustion of anthracene, \(\mathrm{C}_{14} \mathrm{H}_{10}(\mathrm{s}),\) is \(-7067 \mathrm{kJ} / \mathrm{mol}\) \(\mathrm{C}_{14} \mathrm{H}_{10} \cdot\) What is the heat of combustion of citric acid, \(\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{O}_{7},\) expressed in \(\mathrm{kJ} / \mathrm{mol} ?\)

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