A clay pot containing water at \(25^{\circ} \mathrm{C}\) is placed in the shade on a day in which the temperature is \(30^{\circ} \mathrm{C} .\) The outside of the clay pot is kept moist. Will the temperature of the water inside the clay pot (a) increase; (b) decrease; (c) remain the same?

Short Answer

Expert verified
The temperature of the water inside the clay pot will decrease due to evaporation cooling.

Step by step solution

01

Understand Evaporation Cooling

Evaporation is a type of phase transition where a substance changes from a liquid state to a gas state. In this process, the particles of substance need to acquire enough energy to move from the liquid to the gas phase. As the water on the pot evaporates, the energy is taken from the pot, causing a decrease in the pot's (and subsequently the water inside) temperature.
02

Consider the Environmental Temperature

The current environmental temperature is \(30^{\circ} \mathrm{C}\) and the pot is kept in shade. This implies that there is minimal additional heat from the sun, therefore the primary heat source is the environmental air. The water inside the clay pot is initially at \(25^{\circ} \mathrm{C}\), which is less than the environmental temperature.
03

Evaluate Temperature Changes

Due to evaporation cooling, the pot's temperature will decrease further from the initial \(25^{\circ} \mathrm{C}\), and as the pot cools, it also cools the water inside. Therefore, it can be concluded that the temperature of the water inside the clay pot will decrease.

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