What mass of ice can be melted with the same quantity of heat as required to raise the temperature of \(3.50 \mathrm{mol} \mathrm{H}_{2} \mathrm{O}(1)\) by \(50.0^{\circ} \mathrm{C} ?\left[\Delta H_{\text {fusion }}^{\circ}=6.01 \mathrm{kJ} / \mathrm{mol}\right.\) \(\left.\mathrm{H}_{2} \mathrm{O}(\mathrm{s})\right]\)

Short Answer

Expert verified
The number of moles of ice that could be melted using the same amount of heat required to raise the temperature of \(3.50 \mathrm{mol}\) water by \(50.0^{\circ} \mathrm{C}\) can be calculated using the heat of fusion and standard specific heat principles. Then, convert that result from moles to grams using the molar mass of water

Step by step solution

01

Calculate the heat required to raise the temperature of water

Firstly, let's find out how much heat is needed to raise the temperature of liquid water by \(50.0^{\circ} \mathrm{C}\). This can be calculated using the formula Q=mcΔT. Where Q represents heat energy, m is the number of moles, c refers to the specific heat capacity of water (4.18 kJ/mol•K), and ΔT is the change in temperature (50°C in this case). Thus, Q needed for water: \(Q = 3.50 \mathrm{mol} * 4.18 \mathrm{kJ/mol•K} * 50 \mathrm{K}\)
02

Calculate the heat required to melt ice

Next, let's calculate how much heat is needed to change the state of water from solid (ice) to liquid using the same heat found in step 1. This can be done using the formula Q=ΔHfusion*n, where ΔHfusion is the heat of fusion of water (6.01 kJ/mol) and n is the number of moles. Thus, to find out the mass of ice that can be melted, we need to rearrange the formula to n = Q / ΔHfusion, and plug in the values.
03

Adjust for grams

Lastly, remember that to convert the number of moles to grams, we need to multiply number of moles by the molar mass of water (18 g/mol). Thus, the mass of ice that could be melt is: Mass = n * molar mass of water

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