A 0.75 g sample of \(\mathrm{KCl}\) is added to \(35.0 \mathrm{g} \mathrm{H}_{2} \mathrm{O}\) in a Styrofoam cup and stirred until it dissolves. The temperature of the solution drops from 24.8 to \(23.6^{\circ} \mathrm{C}\) (a) Is the process endothermic or exothermic? (b) What is the heat of solution of KCl expressed in kilojoules per mole of KCl?

Short Answer

Expert verified
(a) The process is endothermic. (b) The molar heat of solution of KCl is -17.32 kJ/mol.

Step by step solution

01

Identifying the type of process

The process is endothermic or exothermic based on whether the temperature drops or rises respectively. Given that the temperature drops from \(24.8^{\circ} \mathrm{C}\) to \(23.6^{\circ} \mathrm{C}\), it's clear that it's an endothermic reaction.
02

Calculating change in temperature

\(\Delta T = T_f - T_i =(23.6^{\circ} \mathrm{C} - 24.8^{\circ} \mathrm{C}) = -1.2^{\circ} \mathrm{C} \). Where \(T_i\) and \(T_f\) are the initial and final temperatures respectively.
03

Converting grams to moles

The number of moles of KCl = mass/molar mass = 0.75 g / 74.5513 g/mol = 0.01006 mol.
04

Calculate the heat gained

Using the formula \(q=mc\Delta T\). The specific heat capacity of water (\(c\)) is usually given as 4.18 J/gC. The mass of water (\(m\)) is given as 35g and \(\Delta T\) as calculated in step 2 is -1.2C. Therefore, \(q = 35g * 4.18 J/gC * -1.2C = -174.36 J\).
05

Convert J to kJ and then divide by moles of solute

This will give the heat of solution of KCl in kJ/mol. Since 1 Joule = 0.001 kJ, first convert J to kJ (-174.36 J = -0.17436 kJ) and then divide by number of moles. That is \(-0.17436kJ / 0.01006mol = -17.32 kJ/mol \)

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