In each of the following processes, is any work done when the reaction is carried out at constant pressure in a vessel open to the atmosphere? If so, is work done by the reacting system or on it? (a) Neutralization of \(\mathrm{Ba}(\mathrm{OH})_{2}(\mathrm{aq})\) by \(\mathrm{HCl}(\mathrm{aq}) ;\) (b) conversion of gaseous nitrogen dioxide to gaseous dinitrogen tetroxide; (c) decomposition of calcium carbonate to calcium oxide and carbon dioxide gas.

Short Answer

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For (a) No work is done. For (b) Work is done on the system. For (c) Work is done by the system.

Step by step solution

01

Identify if work is done (a)

The first process is the reaction between Barium hydroxide and Hydrogen Chloride. The chemical reaction is: \[ \mathrm{Ba(OH)_2(aq) + 2HCl(aq) \longrightarrow BaCl_2(aq) + 2H_2O(l)}\]. It is noticeable that there are no gases at any stage of this reaction, hence no volume change. Consequently, no work is done in this case.
02

Identify if work is done (b)

The second process is the conversion of nitrogen dioxide to dinitrogen tetroxide. The chemical reaction is: \[ \mathrm{2NO_2(g) \longrightarrow N_2O_4(g)}\]. In this case, there is a reduction in the number of moles of gas (from 2 moles of NO2 to 1 mole of N2O4), indicating a decrease in volume at constant pressure, so work is done on the system.
03

Identify if work is done (c)

The third process is the decomposition of calcium carbonate to calcium oxide and carbon dioxide gas. The chemical reaction is: \[ \mathrm{CaCO_3(s) \longrightarrow CaO(s) + CO_2(g)}\]. Since there's an increase in the number of moles of gas (from no gaseous reactant to 1 mole of CO2 product), this indicates an increase in volume at constant pressure, so the work is done by the system.

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