What is the change in internal energy of a system if the surroundings (a) transfer 235 J of heat and 128 J of work to the system; (b) absorb 145 J of heat from the system while doing \(98 \mathrm{J}\) of work on the system; (c) exchange no heat, but receive 1.07 kJ of work from the system?

Short Answer

Expert verified
The change in internal energy for the system is (a) 107 J, (b) -243 J, (c) 1070 J

Step by step solution

01

Calculate the change in internal energy for part (a)

For part (a), both heat (Q=235 J) and work (W=128 J) are being transferred to the system. We simply replace those values into the formula: \(ΔU = Q - W\) so it results in \(ΔU = 235 - 128 = 107 J\).
02

Calculate the change in internal energy for part (b)

For part (b), the surroundings are absorbing heat from the system (Q=-145 J) and doing work on it (W=98 J). Plug these values into the equation. However, be sure to make the heat value negative, as it is being taken away from the system: \(ΔU = -145 -98 = -243 J\).
03

Calculate the change in internal energy for part (c)

For part (c), there is no exchange of heat (Q=0) and the system is doing work (W=-1.07 kJ or -1070 J as we need to convert kJ into J). Plugging these values into our formula we get: \(ΔU = 0 - (-1070) = 1070 J\).

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Most popular questions from this chapter

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