Show that the volume of a spherical shell of radius \(r\) and thickness \(d r\) is \(4 \pi r^{2} d r .\) [Hint: This exercise requires calculus.]

Short Answer

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The volume of a spherical shell of radius \(r\) and thickness \(d r\) is \(4\pi r^2 dr\)

Step by step solution

01

Write down the volume of a sphere

The volume, \(V\) of a sphere with radius \(r\) is given by the equation: \(V=\frac{4}{3}\pi r^3\)
02

Differentiate the volume equation with respect to radius

The derivative of \(V\) with respect to \(r\) is given by \(\frac{dV}{dr}= 4\pi r^2\)
03

Calculate the volume of the shell

The volume of the shell, \(dV\) with thickness \(dr\) is given by: \(dV = \frac{dV}{dr} \cdot dr = 4 \pi r^2 dr\)

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