An electron in a one-dimensional box requires a wavelength of \(618 \mathrm{nm}\) to excite an electron from the \(n=2\) level to the \(n=4\) level. Calculate the length of the box.

Short Answer

Expert verified
The length of the box is calculated to be approximately \(3.20 \times 10^{-10}\) meters, or 320 picometers.

Step by step solution

01

Calculate the photon's frequency

First, need to calculate the frequency of the photon. This can be done using the equation \(\Omega = c/\lambda\), where \(c\) is the speed of light. But before substituting the values we need to convert the wavelength from nm to m, which means \(\lambda = 618 \times 10^{-9} m\). Now substitute the speed of light \(c=3.0 \times 10^{8} m/s\) and the converted wavelength in the equation and find the frequency.
02

Calculate the energy of the photon

Next, the energy of the photon is calculated using the equation \(\Delta E = h\Omega\), where \(h\) is Planck's constant (\(h=6.626 \times 10^{-34} Js\)). Substitute the calculated frequency and Planck's constant in the equation to find \(\Delta E\).
03

Apply particle in a box model

Now, apply the particle in a box model's equation for energy difference, which is \(\Delta E = h^2/8mL^2 (n_f^2 - n_i^2)\), where \(n_i\) and \(n_f\) are the initial and final energy levels, and \(m\) is the mass of the electron (\(9.11 \times 10^{-31} kg\)), and \(L\) is the length of the box we need to find. Substitute all known values and solve this equation for \(L\).

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