Write an acceptable value for each of the missing quantum numbers. (a) \(n=3, \ell=?, m_{\ell}=2, m_{s}=+\frac{1}{2}\) (b) \(n=?, \ell=2, m_{\ell}=1, m_{s}=-\frac{1}{2}\) (c) \(n=4, \ell=2, m_{\ell}=0, m_{s}=?\) (d) \(n=?, \ell=0, m_{\ell}=?, m_{s}=?\)

Short Answer

Expert verified
(a) \(l=2\), (b) \(n=3, 4, ...etc.\), (c) \(m_{s}= +\frac{1}{2}, -\frac{1}{2}\), (d) \(n=1, 2, ...etc., m_{\ell}=0, m_{s}= +\frac{1}{2}, -\frac{1}{2}\)

Step by step solution

01

Solve for Missing Quantum Number in (a)

For (a) \(n=3, m_{\ell}=2, m_{s}=+\frac{1}{2}\), we need to find \(\ell\). As \(m_{\ell}\) ranges from \(-l\) to \(l\), \(\ell\) must be equal to or greater than \(m_{\ell}\). The only acceptable value that does not exceed \(n-1\) is \(l=2\).
02

Solve for Missing Quantum Number in (b)

For (b) \(\ell=2, m_{\ell}=1, m_{s}=-\frac{1}{2}\), we need to find \(n\). As \(\ell\) must be smaller than \(n\), the only acceptable value for \(n\) that is larger than \(\ell=2\) is \(n=3\), \(n=4\), and so on.
03

Solve for Missing Quantum Number in (c)

For (c) \(n=4, \ell=2, m_{\ell}=0\), we need to find \(m_{s}\). \(m_{s}\) only has two possible values: \(+\frac{1}{2}\) and \(-\frac{1}{2}\). So either of them is an acceptable value.
04

Solve for Missing Quantum Number in (d)

For (d) \(\ell=0\), we need to find \(n, m_{\ell}, m_{s}\). As \(\ell\) should be less than \(n\), the only acceptable value for \(n\) that is larger than \(\ell=0\) is \(n=1\), \(n=2\), and so on. \(m_{\ell}\) ranges from \(-\ell\) to \(\ell\), so the only possible value for \(m_{\ell}\) here is \(m_{\ell}=0\). \(m_{s}\) only has two possible values: \(+\frac{1}{2}\) and \(-\frac{1}{2}\). So either of them is an acceptable value.

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