Without doing detailed calculations, arrange the following electromagnetic radiation sources in order of increasing frequency: (a) a red traffic light, (b) a \(91.9 \mathrm{MHz}\) radio transmitter, (c) light with a frequency of \(3.0 \times 10^{14} \mathrm{s}^{-1}\) (d) light with a wavelength of \(49 \mathrm{nm}\).

Short Answer

Expert verified
The arranged order of increasing frequency is: a 91.9 MHz radio transmitter (b), light with a frequency of \(3.0 \times 10^{14} s^{-1}\) (c), a red traffic light (a), and light with a wavelength of \(49 nm\) (d).

Step by step solution

01

Frequency of a radio transmitter

Given that (b) a radio transmitter operates at \(91.9 \mathrm{MHz}\), which is equal to \(91.9 \times 10^{6} \mathrm{s^{-1}}\).
02

Frequency of red light

Light from a red traffic light (a) is at the lower frequency end of the visible spectrum, with a frequency approximately around \(4.3 \times 10^{14} \mathrm{s^{-1}}\).
03

Frequency of light

For (c), we are already given light with a frequency of \(3.0 \times 10^{14} \mathrm{s}^{-1}\).
04

Frequency with a wavelength of 49 nm

Using the wave equation and the value of the speed of light \( v = 3.0 \times 10^8 m/s \), the light of wavelength \(49 \mathrm{nm}\) (d) has a frequency \(f = v/\lambda = (3.0 \times 10^{8} m/s) / (49 \times 10^{-9} m) = 6.12 \times 10^{15} \mathrm{s^{-1}}\).
05

Arranging in order of increasing frequency

Arranging these in order of increasing frequency: a radio transmitter (b), light of frequency \(3.0 \times 10^{14} s^{-1}\) (c), red traffic light (a), and light of wavelength \(49 nm\) (d).

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