Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 9: Problem 31

Compare the elements \(\mathrm{Al}, \mathrm{Si}, \mathrm{S},\) and \(\mathrm{Cl}.\) (a) Place the elements in order of increasing ionization energy. (b) Place the elements in order of increasing electron affinity.

Short Answer

Expert verified
For increasing ionization energy, the order of the elements is Al, Si, S, Cl. For increasing electron affinity, the order is identical: Al, Si, S, Cl.

Step by step solution

01

Understand the position of each element on the periodic table

Find the position of the given elements - Al, Si, S, and Cl - on the periodic table. Al is in group 13 and period 3. Si is in group 14 and period 3. S is in group 16 and period 3. Cl is in group 17 and period 3.
02

Order the elements based on ionization energy

Recall that ionization energy increases going from left to right across a period on the periodic table. So, the elements, in increasing order of ionization energy are: Al < Si < S < Cl.
03

Order the elements based on electron affinity

Electron affinity increases across a period from left to right. Following this rule, the elements in increasing order of electron affinity are: Al < Si < S < Cl.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In your own words, define the following terms: (a) isoelectronic; (b) valence- shell electrons; (c) metal; (d) nonmetal; (e) metalloid.

Write balanced equations to represent (a) the displacement of a halide anion from aqueous solution by liquid bromine (b) the reaction with water of an alkali metal with \(Z>50\) (c) the reaction of tetraphosphorus decoxide with water (d) the reaction of aluminum oxide with aqueous sulfuric acid

An ion that is isoelectronic with \(\mathrm{Se}^{2-}\) is (a) \(\mathrm{S}^{2-} ;\) (b) I \(^{-}\) (c) \(\mathrm{Xe} ;\) (d) \(\mathrm{Sr}^{2+}.\)

The most negative electron affinity of the following elements is that of (a) \(\mathrm{Br} ;\) (b) \(\mathrm{Sn} ;\) (c) \(\mathrm{Ba} ;\) (d) Li.

In estimating the boiling point and melting point of bromine in Example \(9-5,\) could we have used Celsius or Fahrenheit instead of Kelvin temperature? Explain.
See all solutions

Recommended explanations on Chemistry Textbooks

Physical Chemistry

Read Explanation

Kinetics

Read Explanation

Making Measurements

Read Explanation

Chemistry Branches

Read Explanation

Ionic and Molecular Compounds

Read Explanation

The Earths Atmosphere

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free